Standard +0.3 This is a straightforward proof by induction with a simple algebraic formula. The partial fraction decomposition 1/(r(r+1)) = 1/r - 1/(r+1) makes the telescoping sum obvious, and the inductive step requires only basic algebraic manipulation. While it's a Further Maths topic, it's a standard textbook exercise requiring no novel insight, making it slightly easier than average overall.
6 Prove by induction that $\sum _ { r = 1 } ^ { n } \frac { 1 } { r ( r + 1 ) } = \frac { n } { n + 1 }$.
\hfill \mbox{\textit{OCR MEI FP1 2006 Q6 [7]}}