OCR C3 2006 June — Question 9 13 marks

Exam BoardOCR
ModuleC3 (Core Mathematics 3)
Year2006
SessionJune
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVolumes of Revolution
TypeMulti-part: volume and related rates
DifficultyStandard +0.8 This question combines volumes of revolution about the y-axis (requiring rearrangement and integration by parts) with related rates of change. Part (i) requires careful setup of the volume integral and non-trivial integration involving exponentials. Part (ii) applies implicit differentiation to connect rates. While systematic, it demands multiple advanced techniques and careful algebraic manipulation beyond standard textbook exercises.
Spec1.07r Chain rule: dy/dx = dy/du * du/dx and connected rates4.08d Volumes of revolution: about x and y axes

9 \includegraphics[max width=\textwidth, alt={}, center]{ebfdf170-99c6-4785-b9d7-201c3425b4c9-4_556_720_676_715} The diagram shows the curve with equation \(y = 2 \ln ( x - 1 )\). The point \(P\) has coordinates ( \(0 , p\) ). The region \(R\), shaded in the diagram, is bounded by the curve and the lines \(x = 0 , y = 0\) and \(y = p\). The units on the axes are centimetres. The region \(R\) is rotated completely about the \(\boldsymbol { y }\)-axis to form a solid.
  1. Show that the volume, \(V \mathrm {~cm} ^ { 3 }\), of the solid is given by $$V = \pi \left( \mathrm { e } ^ { p } + 4 \mathrm { e } ^ { \frac { 1 } { 2 } p } + p - 5 \right) .$$
  2. It is given that the point \(P\) is moving in the positive direction along the \(y\)-axis at a constant rate of \(0.2 \mathrm {~cm} \mathrm {~min} ^ { - 1 }\). Find the rate at which the volume of the solid is increasing at the instant when \(p = 4\), giving your answer correct to 2 significant figures.

AnswerMarks Guidance
(i) Attempt to express \(x\) in terms of \(y\)*M1 obtaining two terms
Obtain \(x = e^{\frac{y}{2}} + 1\)A1 or equiv
State or imply volume involves \(\int\pi x^2\)B1
Attempt to express \(x^2\) in terms of \(y\)*M1 dep *M; expanding to produce at least 3 terms
Obtain \(k\int(e^y + 2e^{\frac{y}{2}} + 1)dy\)A1 any constant \(k\) including 1; allow if \(dy\) absent
Integrate to obtain \(k(e^y + 4e^{\frac{y}{2}} + y)\)A1
Use limits 0 and \(p\)M1 dep *M *M; evidence of use of 0 needed
Obtain \(\pi(e^p + 4e^{\frac{1}{2}p} + p - 5)\)A1 8 AG; necessary detail required
(ii) State or imply \(\frac{dp}{dr} = 0.2\)B1 maybe implied by use of 0.2 in product
Obtain \(\pi(e^p + 2e^{\frac{1}{2}p} + 1)\) as derivative of \(V\)B1
Attempt multiplication of values or expressions for \(\frac{dp}{dr}\) and \(\frac{dV}{dp}\)M1
Obtain \(0.2\pi(e^p + 2e^2 + 1)\)A1√ following their \(\frac{dV}{dp}\) expression
Obtain \(44\)A1 5 or greater accuracy
**(i)** Attempt to express $x$ in terms of $y$ | *M1 | obtaining two terms

Obtain $x = e^{\frac{y}{2}} + 1$ | A1 | or equiv

State or imply volume involves $\int\pi x^2$ | B1 |

Attempt to express $x^2$ in terms of $y$ | *M1 | dep *M; expanding to produce at least 3 terms

Obtain $k\int(e^y + 2e^{\frac{y}{2}} + 1)dy$ | A1 | any constant $k$ including 1; allow if $dy$ absent

Integrate to obtain $k(e^y + 4e^{\frac{y}{2}} + y)$ | A1 |

Use limits 0 and $p$ | M1 | dep *M *M; evidence of use of 0 needed

Obtain $\pi(e^p + 4e^{\frac{1}{2}p} + p - 5)$ | A1 8 | AG; necessary detail required

**(ii)** State or imply $\frac{dp}{dr} = 0.2$ | B1 | maybe implied by use of 0.2 in product

Obtain $\pi(e^p + 2e^{\frac{1}{2}p} + 1)$ as derivative of $V$ | B1 |

Attempt multiplication of values or expressions for $\frac{dp}{dr}$ and $\frac{dV}{dp}$ | M1 |

Obtain $0.2\pi(e^p + 2e^2 + 1)$ | A1√ | following their $\frac{dV}{dp}$ expression

Obtain $44$ | A1 5 | or greater accuracy
9\\
\includegraphics[max width=\textwidth, alt={}, center]{ebfdf170-99c6-4785-b9d7-201c3425b4c9-4_556_720_676_715}

The diagram shows the curve with equation $y = 2 \ln ( x - 1 )$. The point $P$ has coordinates ( $0 , p$ ). The region $R$, shaded in the diagram, is bounded by the curve and the lines $x = 0 , y = 0$ and $y = p$. The units on the axes are centimetres. The region $R$ is rotated completely about the $\boldsymbol { y }$-axis to form a solid.\\
(i) Show that the volume, $V \mathrm {~cm} ^ { 3 }$, of the solid is given by

$$V = \pi \left( \mathrm { e } ^ { p } + 4 \mathrm { e } ^ { \frac { 1 } { 2 } p } + p - 5 \right) .$$

(ii) It is given that the point $P$ is moving in the positive direction along the $y$-axis at a constant rate of $0.2 \mathrm {~cm} \mathrm {~min} ^ { - 1 }$. Find the rate at which the volume of the solid is increasing at the instant when $p = 4$, giving your answer correct to 2 significant figures.

\hfill \mbox{\textit{OCR C3 2006 Q9 [13]}}