3 The equation \(2 x ^ { 3 } + 4 x - 35 = 0\) has one real root.
- Show by calculation that this real root lies between 2 and 3 .
- Use the iterative formula
$$x _ { n + 1 } = \sqrt [ 3 ] { 17.5 - 2 x _ { n } }$$
with a suitable starting value, to find the real root of the equation \(2 x ^ { 3 } + 4 x - 35 = 0\) correct to 2 decimal places. You should show the result of each iteration.