CAIE P1 2020 March — Question 11 9 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2020
SessionMarch
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard trigonometric equations
TypeConvert to quadratic in tan
DifficultyStandard +0.3 Part (a) is a straightforward quadratic in tan x requiring factorization and inverse tan. Part (b) involves discriminant analysis but is standard. Part (c) requires recognizing that tan x has a discontinuity at 90°, making it slightly more conceptually demanding but still routine for P1 level with clear structure and standard techniques throughout.
Spec1.02f Solve quadratic equations: including in a function of unknown1.02g Inequalities: linear and quadratic in single variable1.05o Trigonometric equations: solve in given intervals

11
  1. Solve the equation \(3 \tan ^ { 2 } x - 5 \tan x - 2 = 0\) for \(0 ^ { \circ } \leqslant x \leqslant 180 ^ { \circ }\).
  2. Find the set of values of \(k\) for which the equation \(3 \tan ^ { 2 } x - 5 \tan x + k = 0\) has no solutions.
  3. For the equation \(3 \tan ^ { 2 } x - 5 \tan x + k = 0\), state the value of \(k\) for which there are three solutions in the interval \(0 ^ { \circ } \leqslant x \leqslant 180 ^ { \circ }\), and find these solutions.

Question 11(a):
AnswerMarks Guidance
AnswerMarks Guidance
\((\tan x - 2)(3\tan x + 1) = 0\), or formula or completing the squareM1 Allow reversal of signs in the factors. Must see a method
\(\tan x = 2\) or \(-\frac{1}{3}\)A1
\(x = 63.4°\) (only value in range)B1FT
\(x = 161.6°\) (only value in range)B1FT
Total: 4
Question 11(b):
AnswerMarks Guidance
AnswerMarks Guidance
Apply \(b^2 - 4ac < 0\)M1 SOI. Expect \(25 - 4(3)(k) < 0\), \(\tan x\) must not be in coefficients
\(k > \frac{25}{12}\)A1 Allow \(b^2 - 4ac = 0\) leading to correct \(k > \frac{25}{12}\) for M1A1
Total: 2
Question 11(c):
AnswerMarks Guidance
AnswerMarks Guidance
\(k = 0\)M1 SOI
\(\tan x = 0\) or \(\frac{5}{3}\)A1
\(x = 0°\) or \(180°\) or \(59.0°\)A1 All three required
Total: 3
## Question 11(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $(\tan x - 2)(3\tan x + 1) = 0$, or formula or completing the square | M1 | Allow reversal of signs in the factors. Must see a method |
| $\tan x = 2$ or $-\frac{1}{3}$ | A1 | |
| $x = 63.4°$ (only value in range) | B1FT | |
| $x = 161.6°$ (only value in range) | B1FT | |
| **Total: 4** | | |

## Question 11(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Apply $b^2 - 4ac < 0$ | M1 | SOI. Expect $25 - 4(3)(k) < 0$, $\tan x$ must not be in coefficients |
| $k > \frac{25}{12}$ | A1 | Allow $b^2 - 4ac = 0$ leading to correct $k > \frac{25}{12}$ for M1A1 |
| **Total: 2** | | |

## Question 11(c):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $k = 0$ | M1 | SOI |
| $\tan x = 0$ or $\frac{5}{3}$ | A1 | |
| $x = 0°$ or $180°$ or $59.0°$ | A1 | All three required |
| **Total: 3** | | |
11
\begin{enumerate}[label=(\alph*)]
\item Solve the equation $3 \tan ^ { 2 } x - 5 \tan x - 2 = 0$ for $0 ^ { \circ } \leqslant x \leqslant 180 ^ { \circ }$.
\item Find the set of values of $k$ for which the equation $3 \tan ^ { 2 } x - 5 \tan x + k = 0$ has no solutions.
\item For the equation $3 \tan ^ { 2 } x - 5 \tan x + k = 0$, state the value of $k$ for which there are three solutions in the interval $0 ^ { \circ } \leqslant x \leqslant 180 ^ { \circ }$, and find these solutions.
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2020 Q11 [9]}}