| Exam Board | CAIE |
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| Module | P1 (Pure Mathematics 1) |
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| Year | 2020 |
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| Session | March |
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| Topic | Trig Equations |
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5 Solve the equation
$$\frac { \tan \theta + 3 \sin \theta + 2 } { \tan \theta - 3 \sin \theta + 1 } = 2$$
for \(0 ^ { \circ } \leqslant \theta \leqslant 90 ^ { \circ }\).