Edexcel FP1 2013 January — Question 3 6 marks

Exam BoardEdexcel
ModuleFP1 (Further Pure Mathematics 1)
Year2013
SessionJanuary
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNewton-Raphson method
TypeNewton-Raphson with complex derivative required
DifficultyModerate -0.3 This is a straightforward Newton-Raphson application requiring differentiation of fractional powers (standard FP1 skill) and one iteration of the formula. The derivative is routine, and the calculation involves no conceptual challenges—just careful arithmetic with a calculator. Slightly easier than average due to being a single iteration with no complications.
Spec1.07i Differentiate x^n: for rational n and sums1.09d Newton-Raphson method

3. $$\mathrm { f } ( x ) = 2 x ^ { \frac { 1 } { 2 } } + x ^ { - \frac { 1 } { 2 } } - 5 , \quad x > 0$$
  1. Find \(\mathrm { f } ^ { \prime } ( x )\). The equation \(\mathrm { f } ( x ) = 0\) has a root \(\alpha\) in the interval [4.5, 5.5].
  2. Using \(x _ { 0 } = 5\) as a first approximation to \(\alpha\), apply the Newton-Raphson procedure once to \(\mathrm { f } ( x )\) to find a second approximation to \(\alpha\), giving your answer to 3 significant figures.

AnswerMarks Guidance
(a) \(f'(x) = x^{\frac{1}{2}} - \frac{1}{2}x^{-\frac{3}{2}}\)M1 A1 (2)
(b) \(f(5) = -0.0807\); \(f'(5) = 0.4025\)B1; M1
\(x_1 = x_0 - \frac{f(x_0)}{f'(x_0)} = 5 - \frac{-0.0807}{0.4025}\)M1
\(= 5.2(0)\)A1 Accept 5.2
(4) [6]
Notes:
The B and M marks are implied by a correct answer only with no working or by \(\frac{1}{10}(10\sqrt{5} - 13)\)
(a) M for at least one of \(\pm ax^{\frac{1}{2}}\) or \(\pm bx^{-\frac{3}{2}}\); A for correct (equivalent) answer only
(b) B for awrt -0.0807; first M for attempting their \(f'(5)\); M for correct formula and attempt to substitute; A for awrt 5.20, but accept 5.2
(a) $f'(x) = x^{\frac{1}{2}} - \frac{1}{2}x^{-\frac{3}{2}}$ | M1 A1 | (2)

(b) $f(5) = -0.0807$; $f'(5) = 0.4025$ | B1; M1 | 

$x_1 = x_0 - \frac{f(x_0)}{f'(x_0)} = 5 - \frac{-0.0807}{0.4025}$ | M1 | 

$= 5.2(0)$ | A1 | Accept 5.2

| (4) [6] |

**Notes:**

The B and M marks are implied by a correct answer only with no working or by $\frac{1}{10}(10\sqrt{5} - 13)$

(a) M for at least one of $\pm ax^{\frac{1}{2}}$ or $\pm bx^{-\frac{3}{2}}$; A for correct (equivalent) answer only

(b) B for awrt -0.0807; first M for attempting their $f'(5)$; M for correct formula and attempt to substitute; A for awrt 5.20, but accept 5.2

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3.

$$\mathrm { f } ( x ) = 2 x ^ { \frac { 1 } { 2 } } + x ^ { - \frac { 1 } { 2 } } - 5 , \quad x > 0$$
\begin{enumerate}[label=(\alph*)]
\item Find $\mathrm { f } ^ { \prime } ( x )$.

The equation $\mathrm { f } ( x ) = 0$ has a root $\alpha$ in the interval [4.5, 5.5].
\item Using $x _ { 0 } = 5$ as a first approximation to $\alpha$, apply the Newton-Raphson procedure once to $\mathrm { f } ( x )$ to find a second approximation to $\alpha$, giving your answer to 3 significant figures.
\end{enumerate}

\hfill \mbox{\textit{Edexcel FP1 2013 Q3 [6]}}