Convert to Cartesian (polynomial/rational)

Questions asking to eliminate the parameter from polynomial or rational parametric equations to obtain a Cartesian equation y = f(x) or implicit form, where trigonometric identities are not the primary method.

23 questions · Moderate -0.1

1.03g Parametric equations: of curves and conversion to cartesian
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Edexcel C34 2017 October Q10
13 marks Standard +0.3
10. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{2a6d0dba-d948-4124-9740-a88c17b0be65-32_556_716_237_607} \captionsetup{labelformat=empty} \caption{Figure 2}
\end{figure} Figure 2 shows a sketch of part of the curve \(C\) with parametric equations $$x = \frac { 20 t } { 2 t + 1 } \quad y = t ( t - 4 ) , \quad t > 0$$ The curve cuts the \(x\)-axis at the point \(P\).
  1. Find the \(x\) coordinate of \(P\).
  2. Show that \(\frac { \mathrm { d } y } { \mathrm {~d} x } = \frac { ( t - A ) ( 2 t + 1 ) ^ { 2 } } { B }\) where \(A\) and \(B\) are constants to be found.
    1. Make \(t\) the subject of the formula $$x = \frac { 20 t } { 2 t + 1 }$$
    2. Hence find a cartesian equation of the curve \(C\). Write your answer in the form $$y = \mathrm { f } ( x ) , \quad 0 < x < k$$ where \(\mathrm { f } ( x )\) is a single fraction and \(k\) is a constant to be found.
Edexcel P4 2021 January Q4
7 marks Standard +0.3
4. The curve \(C\) is defined by the parametric equations $$x = \frac { 1 } { t } + 2 \quad y = \frac { 1 - 2 t } { 3 + t } \quad t > 0$$
  1. Show that the equation of \(C\) can be written in the form \(y = \mathrm { g } ( x )\) where g is the function $$\mathrm { g } ( x ) = \frac { a x + b } { c x + d } \quad x > k$$ where \(a , b , c , d\) and \(k\) are integers to be found.
  2. Hence, or otherwise, state the range of g .

Edexcel P4 2022 January Q2
4 marks Standard +0.3
2. The curve \(C\) has parametric equations $$x = \frac { t ^ { 4 } } { 2 t + 1 } \quad y = \frac { t ^ { 3 } } { 2 t + 1 } \quad t > 0$$
  1. Write down \(\frac { x } { y }\) in terms of \(t\), giving your answer in simplest form.
  2. Hence show that all points on \(C\) satisfy the equation $$x ^ { 3 } - 2 x y ^ { 3 } - y ^ { 4 } = 0$$
Edexcel P4 2023 January Q2
6 marks Standard +0.3
  1. A set of points \(P ( x , y )\) is defined by the parametric equations
$$x = \frac { t - 1 } { 2 t + 1 } \quad y = \frac { 6 } { 2 t + 1 } \quad t \neq - \frac { 1 } { 2 }$$
  1. Show that all points \(P ( x , y )\) lie on a straight line.
  2. Hence or otherwise, find the \(x\) coordinate of the point of intersection of this line and the line with equation \(y = x + 12\)
OCR MEI C4 2007 June Q4
4 marks Moderate -0.8
4 A curve is defined by parametric equations $$x = \frac { 1 } { t } - 1 , y = \frac { 2 + t } { 1 + t }$$ Show that the cartesian equation of the curve is \(y = \frac { 3 + 2 x } { 2 + x }\).
OCR MEI C4 Q5
7 marks Moderate -0.8
5 A ball is thrown towards a hedge. Its position relative to the point from which it was thrown is given by the parametric equations $$x = 8 t , y = 10 t - 5 t ^ { 2 }$$
  1. Find the cartesian equation of the trajectory of the ball.
  2. The ball just clears the hedge. What can you say about the height of the hedge?
OCR C4 Q6
11 marks Standard +0.3
6. A curve has parametric equations $$x = \frac { t } { 2 - t } , \quad y = \frac { 1 } { 1 + t } , \quad - 1 < t < 2$$
  1. Show that \(\frac { \mathrm { d } y } { \mathrm {~d} x } = - \frac { 1 } { 2 } \left( \frac { 2 - t } { 1 + t } \right) ^ { 2 }\).
  2. Find an equation for the normal to the curve at the point where \(t = 1\).
  3. Show that the cartesian equation of the curve can be written in the form $$y = \frac { 1 + x } { 1 + 3 x }$$
OCR MEI C4 Q8
4 marks Moderate -0.8
8 A curve is defined by parametric equations $$x = \frac { 1 } { t } - 1 , y = \frac { 2 + t } { 1 + t }$$ Show that the cartesian equation of the curve is \(y = \frac { 3 + 2 x } { 2 + x }\).
OCR MEI C4 Q5
5 marks Moderate -0.3
5 A curve is defined parametrically by the equations $$x = \frac { 1 } { 1 + t } , \quad y = \frac { 1 - t } { 1 + 2 t }$$ Find \(t\) in terms of \(x\). Hence find the cartesian equation of the curve, giving your answer as simply as possible.
OCR C4 2009 June Q5
9 marks Standard +0.3
5 A curve has parametric equations $$x = 2 t + t ^ { 2 } , \quad y = 2 t ^ { 2 } + t ^ { 3 }$$
  1. Express \(\frac { \mathrm { d } y } { \mathrm {~d} x }\) in terms of \(t\) and find the gradient of the curve at the point \(( 3 , - 9 )\).
  2. By considering \(\frac { y } { x }\), find a cartesian equation of the curve, giving your answer in a form not involving fractions.
OCR C4 2010 June Q7
11 marks Moderate -0.3
7 The parametric equations of a curve are \(x = \frac { t + 2 } { t + 1 } , y = \frac { 2 } { t + 3 }\).
  1. Show that \(\frac { \mathrm { d } y } { \mathrm {~d} x } > 0\).
  2. Find the cartesian equation of the curve, giving your answer in a form not involving fractions.
OCR MEI C4 2011 January Q2
5 marks Moderate -0.3
2 A curve is defined parametrically by the equations $$x = \frac { 1 } { 1 + t } , \quad y = \frac { 1 - t } { 1 + 2 t }$$ Find \(t\) in terms of \(x\). Hence find the cartesian equation of the curve, giving your answer as simply as possible.
OCR H240/01 2018 June Q10
10 marks Standard +0.3
10 A curve has parametric equations \(x = t + \frac { 2 } { t }\) and \(y = t - \frac { 2 } { t }\), for \(t \neq 0\).
  1. Find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\) in terms of \(t\), giving your answer in its simplest form.
  2. Explain why the curve has no stationary points.
  3. By considering \(x + y\), or otherwise, find a cartesian equation of the curve, giving your answer in a form not involving fractions or brackets.
Edexcel Paper 1 2021 October Q13
3 marks Standard +0.3
  1. A curve \(C\) has parametric equations
$$x = \frac { t ^ { 2 } + 5 } { t ^ { 2 } + 1 } \quad y = \frac { 4 t } { t ^ { 2 } + 1 } \quad t \in \mathbb { R }$$ Show that all points on \(C\) satisfy $$( x - 3 ) ^ { 2 } + y ^ { 2 } = 4$$
Edexcel Paper 1 Specimen Q5
3 marks Standard +0.3
5. A curve \(C\) has parametric equations $$x = 2 t - 1 , \quad y = 4 t - 7 + \frac { 3 } { t } , \quad t \neq 0$$ Show that the Cartesian equation of the curve \(C\) can be written in the form $$y = \frac { 2 x ^ { 2 } + a x + b } { x + 1 } , \quad x \neq - 1$$ where \(a\) and \(b\) are integers to be found.
OCR MEI Paper 1 2019 June Q12
6 marks Moderate -0.3
12 Fig. 12 shows a curve C with parametric equations \(x = 4 t ^ { 2 } , y = 4 t\). The point P , with parameter \(t\), is a general point on the curve. Q is the point on the line \(x + 4 = 0\) such that PQ is parallel to the \(x\)-axis. R is the point \(( 4,0 )\). \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{59e924e6-8fa9-4035-9173-705fce487bd9-6_766_584_413_255} \captionsetup{labelformat=empty} \caption{Fig. 12}
\end{figure}
  1. Show algebraically that P is equidistant from Q and R .
  2. Find a cartesian equation of C .
OCR MEI Paper 1 2022 June Q8
10 marks Moderate -0.3
8 A particle moves in the \(x - y\) plane so that its position at time \(t\) s is given by \(x = t ^ { 3 } - 8 t , y = t ^ { 2 }\) for \(- 3.5 < t < 3.5\). The units of distance are metres. The graph shows the path of the particle and the direction of travel at the point \(\mathrm { P } ( 8,4 )\). \includegraphics[max width=\textwidth, alt={}, center]{9dd6fc6d-b51e-4a73-ace5-d26a7558032c-07_492_924_415_242}
  1. Find \(\frac { \mathrm { dy } } { \mathrm { dx } }\) in terms of \(t\).
  2. Hence show that the value of \(\frac { \mathrm { dy } } { \mathrm { dx } }\) at P is - 1 .
  3. Find the time at which the particle is travelling in the direction opposite to that at P .
  4. Find the cartesian equation of the path, giving \(x ^ { 2 }\) as a function of \(y\).
OCR MEI Paper 3 2018 June Q8
8 marks Standard +0.8
8 A curve has parametric equations \(x = \frac { t } { 1 + t ^ { 3 } } , y = \frac { t ^ { 2 } } { 1 + t ^ { 3 } }\), where \(t \neq - 1\).
  1. In this question you must show detailed reasoning. Determine the gradient of the curve at the point where \(t = 1\).
  2. Verify that the cartesian equation of the curve is \(x ^ { 3 } + y ^ { 3 } = x y\).
AQA C4 2012 January Q5
11 marks Moderate -0.3
5 A curve is defined by the parametric equations $$x = 8 t ^ { 2 } - t , \quad y = \frac { 3 } { t }$$
  1. Show that the cartesian equation of the curve can be written as \(x y ^ { 2 } + 3 y = k\), stating the value of the integer \(k\).
    (2 marks)
    1. Find an equation of the tangent to the curve at the point \(P\), where \(t = \frac { 1 } { 4 }\).
    2. Verify that the tangent at \(P\) intersects the curve when \(x = \frac { 3 } { 2 }\).
AQA C4 2008 January Q5
10 marks Standard +0.3
5 A curve is defined by the parametric equations \(x = 2 t + \frac { 1 } { t ^ { 2 } } , \quad y = 2 t - \frac { 1 } { t ^ { 2 } }\).
  1. At the point \(P\) on the curve, \(t = \frac { 1 } { 2 }\).
    1. Find the coordinates of \(P\).
    2. Find an equation of the tangent to the curve at \(P\).
  2. Show that the cartesian equation of the curve can be written as $$( x - y ) ( x + y ) ^ { 2 } = k$$ where \(k\) is an integer.
AQA C4 2005 June Q5
10 marks Moderate -0.8
5 A curve is defined by the parametric equations $$x = 2 t + \frac { 1 } { t } , \quad y = \frac { 1 } { t } , \quad t \neq 0$$
  1. Find the coordinates of the point on the curve where \(t = \frac { 1 } { 2 }\).
  2. Show that the cartesian equation of the curve can be written as $$x y - y ^ { 2 } = 2$$
  3. Show that the gradient of the curve at the point \(( 3,2 )\) is 2 .
Pre-U Pre-U 9794/2 2015 June Q7
6 marks Standard +0.3
7 A curve is given parametrically by \(x = 3 t , y = 1 + t ^ { 3 }\) where \(t\) is any real number.
  1. Show that a cartesian equation for this curve is given by \(y = 1 + \frac { 1 } { 27 } x ^ { 3 }\). A second curve is given by \(y = x ^ { 2 } + 4 x - 19\).
  2. Given that the curves intersect at the point \(( 3,2 )\), find the coordinates of all the other points of intersection between the two curves.
Edexcel P4 2022 October Q1
3 marks Moderate -0.8
A curve \(C\) has parametric equations $$x = \frac{t}{t-3}, \quad y = \frac{1}{t} + 2, \quad t \in \mathbb{R}, \quad t > 3$$ Show that all points on \(C\) lie on the curve with Cartesian equation $$y = \frac{ax - 1}{bx}$$ where \(a\) and \(b\) are constants to be found. [3]