Edexcel C34 2018 June — Question 12 9 marks

Exam BoardEdexcel
ModuleC34 (Core Mathematics 3 & 4)
Year2018
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicReciprocal Trig & Identities
TypeDouble angle with reciprocal functions
DifficultyStandard +0.8 Part (a) requires proving an identity involving reciprocal trig functions and double angles, demanding algebraic manipulation of cot and tan into cos/sin form. Part (b) applies this result to solve an equation with compound angles, requiring substitution, double angle application, and careful angle arithmetic within constraints. This goes beyond routine C3/C4 exercises, requiring multi-step reasoning and comfort with reciprocal functions, but remains accessible with standard techniques.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05l Double angle formulae: and compound angle formulae1.05o Trigonometric equations: solve in given intervals

12. (a) Show that $$\cot x - \tan x \equiv 2 \cot 2 x , \quad x \neq 90 n ^ { \circ } , n \in \mathbb { Z }$$ (b) Hence, or otherwise, solve, for \(0 \leqslant \theta < 180 ^ { \circ }\) $$5 + \cot \left( \theta - 15 ^ { \circ } \right) - \tan \left( \theta - 15 ^ { \circ } \right) = 0$$ giving your answers to one decimal place.
[0pt] [Solutions based entirely on graphical or numerical methods are not acceptable.]

12. (a) Show that

$$\cot x - \tan x \equiv 2 \cot 2 x , \quad x \neq 90 n ^ { \circ } , n \in \mathbb { Z }$$

(b) Hence, or otherwise, solve, for $0 \leqslant \theta < 180 ^ { \circ }$

$$5 + \cot \left( \theta - 15 ^ { \circ } \right) - \tan \left( \theta - 15 ^ { \circ } \right) = 0$$

giving your answers to one decimal place.\\[0pt]
[Solutions based entirely on graphical or numerical methods are not acceptable.]

\hfill \mbox{\textit{Edexcel C34 2018 Q12 [9]}}