Edexcel C34 2014 June — Question 4 4 marks

Exam BoardEdexcel
ModuleC34 (Core Mathematics 3 & 4)
Year2014
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIntegration by Substitution
TypeIndefinite integral with linear substitution
DifficultyModerate -0.8 Both parts are standard textbook exercises in integration by substitution/recognition. Part (a) requires recognizing a linear function raised to a power (immediate application of chain rule in reverse), and part (b) is a standard logarithmic form where the numerator is a constant multiple of the derivative of the denominator. These are routine C3/C4 questions requiring pattern recognition rather than problem-solving.
Spec1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)1.08h Integration by substitution

4. Find
  1. \(\int ( 2 x + 3 ) ^ { 12 } \mathrm {~d} x\)
  2. \(\int \frac { 5 x } { 4 x ^ { 2 } + 1 } \mathrm {~d} x\)

Question 4:
Part (a)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\int(2x+3)^{12}\,dx = \frac{(2x+3)^{13}}{(13)(2)} + c\)M1 Gives \(\pm\lambda(2x+3)^{13}\) where \(\lambda\) is constant, or \(\pm\mu(x + \frac{3}{2})^{13}\)
\(\frac{(2x+3)^{13}}{(13)(2)} + c\)A1 Coefficient need not be simplified; ignore \(+c\)
Part (b)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\int\frac{5x}{4x^2+1}\,dt = \frac{5}{8}\ln(4x^2+1) + c\) or \(\frac{5}{8}\ln(x^2 + \frac{1}{4}) + k\)M1 Gives \(\pm\mu\ln(4x^2+1)\) where \(\mu\) is constant, or \(\pm\mu\ln(x^2+\frac{1}{4})\) or \(\pm\mu\ln(k(4x^2+1))\)
\(\frac{5}{8}\ln(4x^2+1) + c\)A1 Modulus sign not needed but allow \(\frac{5}{8}\ln\
# Question 4:

## Part (a)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\int(2x+3)^{12}\,dx = \frac{(2x+3)^{13}}{(13)(2)} + c$ | M1 | Gives $\pm\lambda(2x+3)^{13}$ where $\lambda$ is constant, or $\pm\mu(x + \frac{3}{2})^{13}$ |
| $\frac{(2x+3)^{13}}{(13)(2)} + c$ | A1 | Coefficient need not be simplified; ignore $+c$ |

## Part (b)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\int\frac{5x}{4x^2+1}\,dt = \frac{5}{8}\ln(4x^2+1) + c$ or $\frac{5}{8}\ln(x^2 + \frac{1}{4}) + k$ | M1 | Gives $\pm\mu\ln(4x^2+1)$ where $\mu$ is constant, or $\pm\mu\ln(x^2+\frac{1}{4})$ or $\pm\mu\ln(k(4x^2+1))$ |
| $\frac{5}{8}\ln(4x^2+1) + c$ | A1 | Modulus sign not needed but allow $\frac{5}{8}\ln\|4x^2+1\|$; also allow $0.625\ln(4x^2+1)$; condone lack of $+c$. Note: $\frac{5}{8}\ln 4x^2 + 1$ with no bracket scores M1A0 |

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4. Find
\begin{enumerate}[label=(\alph*)]
\item $\int ( 2 x + 3 ) ^ { 12 } \mathrm {~d} x$
\item $\int \frac { 5 x } { 4 x ^ { 2 } + 1 } \mathrm {~d} x$
\end{enumerate}

\hfill \mbox{\textit{Edexcel C34 2014 Q4 [4]}}