- Given that
$$\begin{array} { l l }
\mathrm { f } ( x ) = \frac { 4 } { 3 x + 5 } , & x > 0
\mathrm {~g} ( x ) = \frac { 1 } { x } , & x > 0
\end{array}$$
- state the range of f,
- find \(\mathrm { f } ^ { - 1 } ( x )\),
- find \(\mathrm { fg } ( x )\).
- Show that the equation \(\mathrm { fg } ( x ) = \mathrm { gf } ( x )\) has no real solutions.