Edexcel C12 2014 January — Question 10 9 marks

Exam BoardEdexcel
ModuleC12 (Core Mathematics 1 & 2)
Year2014
SessionJanuary
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTrigonometric equations in context
TypeSketch transformed/compound trig graph and identify features
DifficultyModerate -0.8 This is a straightforward trigonometric question requiring a sketch of a horizontally shifted cosine curve, finding intercepts by substitution, and solving a basic trig equation using standard angles. All parts use routine techniques with no problem-solving insight needed, making it easier than average for A-level.
Spec1.05f Trigonometric function graphs: symmetries and periodicities1.05g Exact trigonometric values: for standard angles1.05o Trigonometric equations: solve in given intervals

10. The curve \(C\) has equation \(y = \cos \left( x - \frac { \pi } { 3 } \right) , 0 \leqslant x \leqslant 2 \pi\)
  1. In the space below, sketch the curve \(C\).
  2. Write down the exact coordinates of the points at which \(C\) meets the coordinate axes.
  3. Solve, for \(x\) in the interval \(0 \leqslant x \leqslant 2 \pi\), $$\cos \left( x - \frac { \pi } { 3 } \right) = \frac { 1 } { \sqrt { 2 } }$$ giving your answers in the form \(k \pi\), where \(k\) is a rational number.

Question 10:
Part (a):
AnswerMarks Guidance
Sketch of harmonic curve (sine or cosine); correct section and position relative to axesM1, A1 Must be only one cycle; positive \(y\)-intercept; positive gradient at start and finish; solely \(x \geq 0\)
Part (b):
AnswerMarks Guidance
\((0, \frac{1}{2})\)B1
\(\left(\frac{5\pi}{6}, 0\right)\) or \((150°, 0)\) and \(\left(\frac{11\pi}{6}, 0\right)\) or \((330°, 0)\)B1, B1 Each answer cao; extra answers in range lose last B1
Part (c):
AnswerMarks Guidance
\(\left(x - \frac{\pi}{3}\right) = \frac{\pi}{4}\) or \(-\frac{\pi}{4}\)M1 Uses inverse cos correctly to obtain at least one correct answer
\(x = \frac{7\pi}{12}\) or \(x = \frac{\pi}{12}\)M1 A1 A1 Second M1: adds \(\frac{\pi}{3}\) to previous answer; one correct answer A1; both correct A1; extra answers in range lose final A1
## Question 10:

### Part (a):
| Sketch of harmonic curve (sine or cosine); correct section and position relative to axes | M1, A1 | Must be only one cycle; positive $y$-intercept; positive gradient at start and finish; solely $x \geq 0$ |

### Part (b):
| $(0, \frac{1}{2})$ | B1 | |
| $\left(\frac{5\pi}{6}, 0\right)$ or $(150°, 0)$ and $\left(\frac{11\pi}{6}, 0\right)$ or $(330°, 0)$ | B1, B1 | Each answer cao; extra answers in range lose last B1 |

### Part (c):
| $\left(x - \frac{\pi}{3}\right) = \frac{\pi}{4}$ or $-\frac{\pi}{4}$ | M1 | Uses inverse cos correctly to obtain at least one correct answer |
| $x = \frac{7\pi}{12}$ or $x = \frac{\pi}{12}$ | M1 A1 A1 | Second M1: adds $\frac{\pi}{3}$ to previous answer; one correct answer A1; both correct A1; extra answers in range lose final A1 |

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10. The curve $C$ has equation $y = \cos \left( x - \frac { \pi } { 3 } \right) , 0 \leqslant x \leqslant 2 \pi$
\begin{enumerate}[label=(\alph*)]
\item In the space below, sketch the curve $C$.
\item Write down the exact coordinates of the points at which $C$ meets the coordinate axes.
\item Solve, for $x$ in the interval $0 \leqslant x \leqslant 2 \pi$,

$$\cos \left( x - \frac { \pi } { 3 } \right) = \frac { 1 } { \sqrt { 2 } }$$

giving your answers in the form $k \pi$, where $k$ is a rational number.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C12 2014 Q10 [9]}}