Edexcel C12 2014 January — Question 5 7 marks

Exam BoardEdexcel
ModuleC12 (Core Mathematics 1 & 2)
Year2014
SessionJanuary
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicArithmetic Sequences and Series
TypePeriodic or repeating sequence
DifficultyStandard +0.8 This recurrence relation question requires students to discover a periodic pattern (cycle of 3 values) through calculation, then apply this insight to find distant terms and sum 99 terms. While the arithmetic is straightforward, recognizing the periodicity and using it strategically for parts (b) and (c) requires problem-solving beyond routine sequence exercises, making it moderately challenging for C1/C2 level.
Spec1.04e Sequences: nth term and recurrence relations

5. A sequence is defined by $$\begin{aligned} u _ { 1 } & = 3 \\ u _ { n + 1 } & = 2 - \frac { 4 } { u _ { n } } , \quad n \geqslant 1 \end{aligned}$$ Find the exact values of
  1. \(u _ { 2 } , u _ { 3 }\) and \(u _ { 4 }\)
  2. \(u _ { 61 }\)
  3. \(\sum _ { i = 1 } ^ { 99 } u _ { i }\)

Question 5:
Part (a)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(u_2 = 2 - \frac{4}{\frac{2}{3}} = \frac{2}{3}\), \(u_3 = 2 - \frac{4}{\frac{2}{3}} = -4\), \(u_4 = 2 - \frac{4}{-4} = 3\)M1 A1 A1 M1: Attempt to use formula correctly. A1: two correct answers. A1: 3 correct answers (allow \(0.\overline{6}\) but not \(0.667\))
[3]
Part (b)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(u_{61} = 3\)B1 B1: cao. NB Use of AP is B0
[1]
Part (c)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\sum_{i=1}^{99} u_i = (3 + \frac{2}{3} - 4) + (3 + \frac{2}{3} - 4) + \ldots\)M1 M1: Uses sum of at least 3 terms found from part (a). Attempt to sum an AP is M0
\(\sum_{i=1}^{99} u_i = 33 \times (\ldots + \ldots + \ldots)\), \(= -11\)A1, A1 A1: obtains \(33 \times\) (sum of three adjacent terms). A1: \(-11\) cao. N.B. Use of \(n=99\) is M1A0A0
[3]
# Question 5:

## Part (a)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $u_2 = 2 - \frac{4}{\frac{2}{3}} = \frac{2}{3}$, $u_3 = 2 - \frac{4}{\frac{2}{3}} = -4$, $u_4 = 2 - \frac{4}{-4} = 3$ | M1 A1 A1 | M1: Attempt to use formula correctly. A1: two correct answers. A1: 3 correct answers (allow $0.\overline{6}$ but not $0.667$) |
| | [3] | |

## Part (b)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $u_{61} = 3$ | B1 | B1: cao. NB Use of AP is B0 |
| | [1] | |

## Part (c)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\sum_{i=1}^{99} u_i = (3 + \frac{2}{3} - 4) + (3 + \frac{2}{3} - 4) + \ldots$ | M1 | M1: Uses sum of at least 3 terms found from part (a). Attempt to sum an AP is M0 |
| $\sum_{i=1}^{99} u_i = 33 \times (\ldots + \ldots + \ldots)$, $= -11$ | A1, A1 | A1: obtains $33 \times$ (sum of three adjacent terms). A1: $-11$ cao. N.B. Use of $n=99$ is M1A0A0 |
| | [3] | |

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5. A sequence is defined by

$$\begin{aligned}
u _ { 1 } & = 3 \\
u _ { n + 1 } & = 2 - \frac { 4 } { u _ { n } } , \quad n \geqslant 1
\end{aligned}$$

Find the exact values of
\begin{enumerate}[label=(\alph*)]
\item $u _ { 2 } , u _ { 3 }$ and $u _ { 4 }$
\item $u _ { 61 }$
\item $\sum _ { i = 1 } ^ { 99 } u _ { i }$
\end{enumerate}

\hfill \mbox{\textit{Edexcel C12 2014 Q5 [7]}}