Edexcel C12 2014 January — Question 11 8 marks

Exam BoardEdexcel
ModuleC12 (Core Mathematics 1 & 2)
Year2014
SessionJanuary
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicArithmetic Sequences and Series
TypeArithmetic progression with parameters
DifficultyModerate -0.8 This is a straightforward arithmetic sequence question requiring only standard techniques: using the common difference property to find p, applying the nth term formula, and deriving the sum formula. All parts are routine applications of well-practiced formulas with no problem-solving insight needed, making it easier than average but not trivial due to the algebraic manipulation required.
Spec1.04g Sigma notation: for sums of series1.04h Arithmetic sequences: nth term and sum formulae

11. The first three terms of an arithmetic series are \(60,4 p\) and \(2 p - 6\) respectively.
  1. Show that \(p = 9\)
  2. Find the value of the 20th term of this series.
  3. Prove that the sum of the first \(n\) terms of this series is given by the expression $$12 n ( 6 - n )$$ \includegraphics[max width=\textwidth, alt={}, center]{e878227b-d625-4ef2-ac49-a9dc05c5321a-27_106_68_2615_1877}

Question 11:
Part (a):
AnswerMarks Guidance
Uses \((2p-6) - 4p = 4p - 60\) or \(4p = \frac{60+(2p-6)}{2}\) or two correct equations with \(d\); so \(p = 9\)M1, A1* Correct equation to enable \(p\) to be found or two correct simultaneous equations
Part (b):
AnswerMarks Guidance
Uses \(a + 19d\) with \(a = 60\); finds \(d = 36 - 60 = -24\); obtains \(-396\)M1, B1, A1 \(d = -24\) seen in (a) or (b); need 20 terms for M1; cso
Part (c):
AnswerMarks Guidance
Uses \(\frac{n}{2}(2 \times 60 + (n-1)d)\); uses \(\frac{n}{2}(2\times 60 - 24(n-1))\)M1, A1 Correct formula with their value of \(d\)
\(= 12n(6-n)\)A1* Given answer — must be no errors to award this mark
## Question 11:

### Part (a):
| Uses $(2p-6) - 4p = 4p - 60$ or $4p = \frac{60+(2p-6)}{2}$ or two correct equations with $d$; so $p = 9$ | M1, A1* | Correct equation to enable $p$ to be found or two correct simultaneous equations |

### Part (b):
| Uses $a + 19d$ with $a = 60$; finds $d = 36 - 60 = -24$; obtains $-396$ | M1, B1, A1 | $d = -24$ seen in (a) or (b); need 20 terms for M1; cso |

### Part (c):
| Uses $\frac{n}{2}(2 \times 60 + (n-1)d)$; uses $\frac{n}{2}(2\times 60 - 24(n-1))$ | M1, A1 | Correct formula with their value of $d$ |
| $= 12n(6-n)$ | A1* | Given answer — must be no errors to award this mark |
11. The first three terms of an arithmetic series are $60,4 p$ and $2 p - 6$ respectively.
\begin{enumerate}[label=(\alph*)]
\item Show that $p = 9$
\item Find the value of the 20th term of this series.
\item Prove that the sum of the first $n$ terms of this series is given by the expression

$$12 n ( 6 - n )$$

\includegraphics[max width=\textwidth, alt={}, center]{e878227b-d625-4ef2-ac49-a9dc05c5321a-27_106_68_2615_1877}
\end{enumerate}

\hfill \mbox{\textit{Edexcel C12 2014 Q11 [8]}}