CAIE Further Paper 4 2023 November — Question 3 8 marks

Exam BoardCAIE
ModuleFurther Paper 4 (Further Paper 4)
Year2023
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicT-tests (unknown variance)
TypePaired sample t-test
DifficultyStandard +0.3 This is a straightforward paired t-test with clearly structured data requiring standard hypothesis test procedure (calculate differences, find mean/SD, compute test statistic, compare to critical value). Part (b) asks for a routine assumption. The question follows a standard template with no novel insights required, making it slightly easier than average for Further Maths statistics.
Spec5.03a Continuous random variables: pdf and cdf5.05c Hypothesis test: normal distribution for population mean

3 Scientists are studying the effects of exercise on LDL blood cholesterol levels. Over a three-month period, a large group of people exercised for 20 minutes each day. For a randomly chosen sample of 10 of these people, the LDL blood cholesterol levels were measured at the beginning and the end of the three-month period. The results, measured in suitable units, are as follows.
\cline { 2 - 12 } \multicolumn{1}{c|}{}Person\(A\)\(B\)\(C\)\(D\)\(E\)\(F\)\(G\)\(H\)\(I\)
\multirow{2}{*}{
Cholesterol
level
}
Beginning72841209010213564758088
\cline { 2 - 12 }End64761059210511567757584
  1. Test, at the \(2.5 \%\) significance level, whether there is evidence that the population mean LDL blood cholesterol level has reduced by more than 2 units after the three-month period.
  2. State any assumption that you have made in part (a). \includegraphics[max width=\textwidth, alt={}, center]{44829994-2ef0-488d-aa3b-99fb0e36d733-06_399_1383_269_324} As shown in the diagram, the continuous random variable \(X\) has probability density function f given by $$f ( x ) = \begin{cases} m x & 0 \leqslant x \leqslant 2 \\ \frac { k } { x ^ { 2 } } + c & 2 \leqslant x \leqslant 6 \\ 0 & \text { otherwise } \end{cases}$$ where \(m , k\) and \(c\) are constants.

Question 3(a):
AnswerMarks Guidance
AnswerMark Guidance
\(H_0: \mu_B - \mu_E = 2\); \(H_1: \mu_B - \mu_E > 2\)B1 May use \(\mu_d\), but must be consistent with direction of differences found
Differences: 8 \8 \ 15 \
\(\sum d = 52\), \(\sum d^2 = 816\), \(s^2 = \frac{1}{9}\left(816 - \frac{52^2}{10}\right) = \frac{2728}{45} = 60.62\)M1 Their values but must see 9 and 10 used correctly
\(t = \dfrac{\frac{52}{10} - 2}{\sqrt{\frac{s^2}{10}}}\)M1
\(t = 1.29967,\ 1.30\)A1
Tabular value \(= 2.262\). \(1.30 < 2.262\), accept \(H_0\)M1 Allow 'not significant'
Insufficient evidence to suggest that cholesterol level has reduced by more than 2A1 CWO. Correct conclusion in context, following correct work, level of uncertainty in language. A0 if hypotheses wrong way round or missing
Question 3(b):
AnswerMarks Guidance
AnswerMark Guidance
Population differences are normally distributedB1
## Question 3(a):

| Answer | Mark | Guidance |
|--------|------|----------|
| $H_0: \mu_B - \mu_E = 2$; $H_1: \mu_B - \mu_E > 2$ | B1 | May use $\mu_d$, but must be consistent with direction of differences found |
| Differences: 8 \| 8 \| 15 \| $-2$ \| $-3$ \| 20 \| $-3$ \| 0 \| 5 \| 4 | M1 | Differences, at most 2 errors |
| $\sum d = 52$, $\sum d^2 = 816$, $s^2 = \frac{1}{9}\left(816 - \frac{52^2}{10}\right) = \frac{2728}{45} = 60.62$ | M1 | Their values but must see 9 and 10 used correctly |
| $t = \dfrac{\frac{52}{10} - 2}{\sqrt{\frac{s^2}{10}}}$ | M1 | |
| $t = 1.29967,\ 1.30$ | A1 | |
| Tabular value $= 2.262$. $1.30 < 2.262$, accept $H_0$ | M1 | Allow 'not significant' |
| Insufficient evidence to suggest that cholesterol level has reduced by more than 2 | A1 | CWO. Correct conclusion in context, following correct work, level of uncertainty in language. A0 if hypotheses wrong way round or missing |

---

## Question 3(b):

| Answer | Mark | Guidance |
|--------|------|----------|
| **Population differences** are **normally** distributed | B1 | |

---
3 Scientists are studying the effects of exercise on LDL blood cholesterol levels. Over a three-month period, a large group of people exercised for 20 minutes each day. For a randomly chosen sample of 10 of these people, the LDL blood cholesterol levels were measured at the beginning and the end of the three-month period. The results, measured in suitable units, are as follows.

\begin{center}
\begin{tabular}{ | c | l | c | c | c | c | c | c | c | c | c | c | }
\cline { 2 - 12 }
\multicolumn{1}{c|}{} & \multicolumn{1}{c|}{} & Person & $A$ & $B$ & $C$ & $D$ & $E$ & $F$ & $G$ & $H$ & $I$ \\
\hline
\multirow{2}{*}{\begin{tabular}{ c }
Cholesterol \\
level \\
\end{tabular}} & Beginning & 72 & 84 & 120 & 90 & 102 & 135 & 64 & 75 & 80 & 88 \\
\cline { 2 - 12 }
 & End & 64 & 76 & 105 & 92 & 105 & 115 & 67 & 75 & 75 & 84 \\
\hline
\end{tabular}
\end{center}
\begin{enumerate}[label=(\alph*)]
\item Test, at the $2.5 \%$ significance level, whether there is evidence that the population mean LDL blood cholesterol level has reduced by more than 2 units after the three-month period.
\item State any assumption that you have made in part (a).\\

\includegraphics[max width=\textwidth, alt={}, center]{44829994-2ef0-488d-aa3b-99fb0e36d733-06_399_1383_269_324}

As shown in the diagram, the continuous random variable $X$ has probability density function f given by

$$f ( x ) = \begin{cases} m x & 0 \leqslant x \leqslant 2 \\ \frac { k } { x ^ { 2 } } + c & 2 \leqslant x \leqslant 6 \\ 0 & \text { otherwise } \end{cases}$$

where $m , k$ and $c$ are constants.
\end{enumerate}

\hfill \mbox{\textit{CAIE Further Paper 4 2023 Q3 [8]}}