CAIE Further Paper 4 2020 June — Question 4 8 marks

Exam BoardCAIE
ModuleFurther Paper 4 (Further Paper 4)
Year2020
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProbability Generating Functions
TypeFind PGF of sum of independent variables
DifficultyStandard +0.8 This is a standard PGF question requiring knowledge that G_Y(t) = [G_X(t)]^2 for sum of independent variables, followed by polynomial expansion and differentiation. While mechanical, it involves Further Maths content (PGFs are UFM-only), multiple steps including algebraic manipulation of a cubic squared, and applying PGF properties for expectation/variance. More demanding than typical A-level but routine for Further Maths students who know the theory.
Spec5.02a Discrete probability distributions: general

4 The discrete random variable \(X\) has probability generating function \(\mathrm { G } _ { \mathrm { X } } ( \mathrm { t } )\) given by $$G _ { X } ( t ) = 0.2 t + 0.5 t ^ { 2 } + 0.3 t ^ { 3 }$$ The random variable \(Y\) is the sum of two independent observations of \(X\).
  1. Find the probability generating function of \(Y\), giving your answer as an expanded polynomial in \(t\). [3]
  2. Use the probability generating function of \(Y\) to find \(\mathrm { E } ( Y )\) and \(\operatorname { Var } ( Y )\).

Question 4:
Part 4(a):
AnswerMarks
\(G_X(t) = 0.2t + 0.5t^2 + 0.3t^3\)B1
\(G_Y(t) = \left(0.2t + 0.5t^2 + 0.3t^3\right)^2\)M1
\(= 0.04t^2 + 0.2t^3 + 0.37t^4 + 0.3t^5 + 0.09t^6\)A1
Part 4(b):
AnswerMarks
\(G'_Y(t) = 0.08t + 0.6t^2 + 1.48t^3 + 1.5t^4 + 0.54t^5\)M1
\(E(Y) = 4.2\)A1
\(G''_Y(t) = 0.08 + 1.2t + 4.44t^2 + 6t^3 + 2.7t^4\)M1
Use \(G''_Y(1) + G'_Y(1) - (G'_Y(1))^2\)M1
\(\text{Var}(Y) = 14.42 + 4.2 - 4.2^2 = 0.98\)A1
## Question 4:

**Part 4(a):**

$G_X(t) = 0.2t + 0.5t^2 + 0.3t^3$ | B1 |

$G_Y(t) = \left(0.2t + 0.5t^2 + 0.3t^3\right)^2$ | M1 |

$= 0.04t^2 + 0.2t^3 + 0.37t^4 + 0.3t^5 + 0.09t^6$ | A1 |

**Part 4(b):**

$G'_Y(t) = 0.08t + 0.6t^2 + 1.48t^3 + 1.5t^4 + 0.54t^5$ | M1 |

$E(Y) = 4.2$ | A1 |

$G''_Y(t) = 0.08 + 1.2t + 4.44t^2 + 6t^3 + 2.7t^4$ | M1 |

Use $G''_Y(1) + G'_Y(1) - (G'_Y(1))^2$ | M1 |

$\text{Var}(Y) = 14.42 + 4.2 - 4.2^2 = 0.98$ | A1 |

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4 The discrete random variable $X$ has probability generating function $\mathrm { G } _ { \mathrm { X } } ( \mathrm { t } )$ given by

$$G _ { X } ( t ) = 0.2 t + 0.5 t ^ { 2 } + 0.3 t ^ { 3 }$$

The random variable $Y$ is the sum of two independent observations of $X$.
\begin{enumerate}[label=(\alph*)]
\item Find the probability generating function of $Y$, giving your answer as an expanded polynomial in $t$. [3]
\item Use the probability generating function of $Y$ to find $\mathrm { E } ( Y )$ and $\operatorname { Var } ( Y )$.
\end{enumerate}

\hfill \mbox{\textit{CAIE Further Paper 4 2020 Q4 [8]}}