CAIE Further Paper 4 2020 June — Question 6 11 marks

Exam BoardCAIE
ModuleFurther Paper 4 (Further Paper 4)
Year2020
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicWilcoxon tests
TypeJustifying choice of test
DifficultyModerate -0.3 Part (a) requires recalling standard conditions for Wilcoxon rank-sum test (independent samples, ordinal data, no normality assumption) - straightforward bookwork. Part (b) involves ranking 24 values, summing ranks, and comparing to critical values - computational but routine application of a standard procedure with no conceptual challenges beyond careful arithmetic.
Spec5.07a Non-parametric tests: when to use5.07b Sign test: and Wilcoxon signed-rank5.07d Paired vs two-sample: selection

6 A biologist is studying the effect of nutrients on the heights to which plants grow. A random sample of 24 similar young plants is divided into two equal groups \(A\) and \(B\). The plants in group \(A\) are fed with nutrients and water and the plants in group \(B\) are given only water. After four weeks, the height, in cm, of each plant is measured and the results are as follows.
Group \(A\)12.311.812.113.211.110.613.812.012.212.413.513.9
Group \(B\)11.710.810.911.311.212.611.010.511.912.510.711.6
The biologist decides to carry out a test at the \(5 \%\) significance level to test whether the nutrients have resulted in an increase in growth.
  1. She carries out a Wilcoxon rank-sum test. Give a reason why this is an appropriate choice of test.
  2. Carry out the Wilcoxon rank-sum test for these results.
    If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.

Question 6:
Part 6(a):
AnswerMarks
Difference of location test for populations not known to be normalB1
Question 6(b):
AnswerMarks Guidance
AnswerMarks Guidance
Ranking table completed correctly (two columns: values with ranks 10–24 for x-group, values with ranks 1–20 for y-group as shown)M1 Method for ranking all 24 values
Total ranks: 109 or 191A1 Either correct rank sum
\(H_0: m_x = m_y \quad H_1: m_x > m_y\)B1 Both hypotheses correct in terms of medians
Use normal approximation with attempts at mean and varianceM1
mean \(= 150\), variance \(= 300\)A1 Both correct
\(\dfrac{109.5 - 150}{\sqrt{300}} = -2.338\)M1A1 Continuity correction \(\pm 0.5\) applied; correct z-value
Probability \(= 0.0097\)A1
This is less than \(0.05\), so reject \(H_0\)M1 Correct comparison and conclusion
There is evidence of an effect on growthA1 Conclusion in context
Total10
## Question 6:

**Part 6(a):**

Difference of location test for populations not known to be normal | B1 |

## Question 6(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Ranking table completed correctly (two columns: values with ranks 10–24 for x-group, values with ranks 1–20 for y-group as shown) | M1 | Method for ranking all 24 values |
| Total ranks: 109 or 191 | A1 | Either correct rank sum |
| $H_0: m_x = m_y \quad H_1: m_x > m_y$ | B1 | Both hypotheses correct in terms of medians |
| Use normal approximation with attempts at mean and variance | M1 | |
| mean $= 150$, variance $= 300$ | A1 | Both correct |
| $\dfrac{109.5 - 150}{\sqrt{300}} = -2.338$ | M1A1 | Continuity correction $\pm 0.5$ applied; correct z-value |
| Probability $= 0.0097$ | A1 | |
| This is less than $0.05$, so reject $H_0$ | M1 | Correct comparison and conclusion |
| There is evidence of an effect on growth | A1 | Conclusion in context |
| **Total** | **10** | |
6 A biologist is studying the effect of nutrients on the heights to which plants grow. A random sample of 24 similar young plants is divided into two equal groups $A$ and $B$. The plants in group $A$ are fed with nutrients and water and the plants in group $B$ are given only water. After four weeks, the height, in cm, of each plant is measured and the results are as follows.

\begin{center}
\begin{tabular}{ | l | l | l | l | l | l | l | l | l | l | l | l | l | }
\hline
Group $A$ & 12.3 & 11.8 & 12.1 & 13.2 & 11.1 & 10.6 & 13.8 & 12.0 & 12.2 & 12.4 & 13.5 & 13.9 \\
\hline
Group $B$ & 11.7 & 10.8 & 10.9 & 11.3 & 11.2 & 12.6 & 11.0 & 10.5 & 11.9 & 12.5 & 10.7 & 11.6 \\
\hline
\end{tabular}
\end{center}

The biologist decides to carry out a test at the $5 \%$ significance level to test whether the nutrients have resulted in an increase in growth.
\begin{enumerate}[label=(\alph*)]
\item She carries out a Wilcoxon rank-sum test. Give a reason why this is an appropriate choice of test.
\item Carry out the Wilcoxon rank-sum test for these results.\\

If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.
\end{enumerate}

\hfill \mbox{\textit{CAIE Further Paper 4 2020 Q6 [11]}}