SPS SPS SM 2025 November — Question 6 8 marks

Exam BoardSPS
ModuleSPS SM (SPS SM)
Year2025
SessionNovember
Marks8
TopicSequences and series, recurrence and convergence
TypeRecurrence relation solving for closed form
DifficultyStandard +0.8 This is a moderately challenging recurrence relation problem requiring algebraic manipulation, summation techniques, and pattern recognition. Part (a) involves computing several terms and solving a cubic equation. Part (b) requires recognizing that the telescoping nature simplifies via the recurrence relation definition, which is a non-trivial insight for most students.
Spec1.04e Sequences: nth term and recurrence relations1.04g Sigma notation: for sums of series

A sequence \(t_1, t_2, t_3, t_4, t_5, \ldots\) is given by $$t_{n+1} = at_n + 3n + 2, \quad t \in \mathbb{N}, \quad t_1 = -2,$$ where \(a\) is a non zero constant.
  1. Given that \(\sum_{r=1}^{3} (r^3 + t_r) = 12\), determine the possible values of \(a\). [4]
  2. Evaluate \(\sum_{r=8}^{31} (t_{r+1} - at_r)\). [4]

A sequence $t_1, t_2, t_3, t_4, t_5, \ldots$ is given by
$$t_{n+1} = at_n + 3n + 2, \quad t \in \mathbb{N}, \quad t_1 = -2,$$
where $a$ is a non zero constant.

\begin{enumerate}[label=(\alph*)]
\item Given that $\sum_{r=1}^{3} (r^3 + t_r) = 12$, determine the possible values of $a$. [4]

\item Evaluate $\sum_{r=8}^{31} (t_{r+1} - at_r)$. [4]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS SM 2025 Q6 [8]}}