SPS SPS FM Pure 2022 February — Question 4 9 marks

Exam BoardSPS
ModuleSPS FM Pure (SPS FM Pure)
Year2022
SessionFebruary
Marks9
Topic3x3 Matrices
TypeMatrix equation solving (AB = C)
DifficultyStandard +0.3 This is a straightforward Further Maths matrices question testing basic concepts: matrix multiplication/addition compatibility (routine recall), finding constants from a matrix equation (algebraic manipulation), deducing an inverse from AB=λI (direct application), and finding when a determinant equals zero (standard calculation with trigonometric simplification). All parts are textbook exercises requiring no novel insight, making it slightly easier than average even for Further Maths.
Spec4.03a Matrix language: terminology and notation4.03b Matrix operations: addition, multiplication, scalar4.03l Singular/non-singular matrices4.03o Inverse 3x3 matrix

  1. \(\mathbf{A}\) is a 2 by 2 matrix and \(\mathbf{B}\) is a 2 by 3 matrix. Giving a reason for your answer, explain whether it is possible to evaluate
    1. \(\mathbf{AB}\)
    2. \(\mathbf{A} + \mathbf{B}\)
    [2]
  2. Given that $$\begin{pmatrix} -5 & 3 & 1 \\ a & 0 & 0 \\ b & a & b \end{pmatrix} \begin{pmatrix} 0 & 5 & 0 \\ 2 & 12 & -1 \\ -1 & -11 & 3 \end{pmatrix} = \lambda \mathbf{I}$$ where \(a\), \(b\) and \(\lambda\) are constants,
    1. determine • the value of \(\lambda\) • the value of \(a\) • the value of \(b\)
    2. Hence deduce the inverse of the matrix \(\begin{pmatrix} -5 & 3 & 1 \\ a & 0 & 0 \\ b & a & b \end{pmatrix}\)
    [3]
  3. Given that $$\mathbf{M} = \begin{pmatrix} 1 & 1 & 1 \\ 0 & \sin\theta & \cos\theta \\ 0 & \cos 2\theta & \sin 2\theta \end{pmatrix} \quad \text{where } 0 \leqslant \theta < \pi$$ determine the values of \(\theta\) for which the matrix \(\mathbf{M}\) is singular. [4]

\begin{enumerate}[label=(\roman*)]
\item $\mathbf{A}$ is a 2 by 2 matrix and $\mathbf{B}$ is a 2 by 3 matrix.

Giving a reason for your answer, explain whether it is possible to evaluate
\begin{enumerate}[label=(\alph*)]
\item $\mathbf{AB}$
\item $\mathbf{A} + \mathbf{B}$
\end{enumerate}
[2]

\item Given that
$$\begin{pmatrix} -5 & 3 & 1 \\ a & 0 & 0 \\ b & a & b \end{pmatrix} \begin{pmatrix} 0 & 5 & 0 \\ 2 & 12 & -1 \\ -1 & -11 & 3 \end{pmatrix} = \lambda \mathbf{I}$$

where $a$, $b$ and $\lambda$ are constants,

\begin{enumerate}[label=(\alph*)]
\item determine
• the value of $\lambda$
• the value of $a$
• the value of $b$

\item Hence deduce the inverse of the matrix $\begin{pmatrix} -5 & 3 & 1 \\ a & 0 & 0 \\ b & a & b \end{pmatrix}$
\end{enumerate}
[3]

\item Given that
$$\mathbf{M} = \begin{pmatrix} 1 & 1 & 1 \\ 0 & \sin\theta & \cos\theta \\ 0 & \cos 2\theta & \sin 2\theta \end{pmatrix} \quad \text{where } 0 \leqslant \theta < \pi$$

determine the values of $\theta$ for which the matrix $\mathbf{M}$ is singular. [4]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS FM Pure 2022 Q4 [9]}}