SPS SPS FM Pure 2022 February — Question 1 7 marks

Exam BoardSPS
ModuleSPS FM Pure (SPS FM Pure)
Year2022
SessionFebruary
Marks7
TopicPartial Fractions
TypeTwo linear factors in denominator
DifficultyModerate -0.3 Part (a) is a routine partial fractions decomposition with linear factors. Part (b) requires recognizing a telescoping series, which is a standard Further Maths technique, but the algebraic manipulation to express the final result as a single fraction adds minor complexity. Overall, this is a straightforward textbook exercise testing standard methods with no novel insight required.
Spec1.02y Partial fractions: decompose rational functions4.06b Method of differences: telescoping series

  1. Express \(\frac{1}{(2r-1)(2r+1)}\) in partial fractions. [3]
  2. Hence find \(\sum_{r=1}^{n}\frac{1}{(2r-1)(2r+1)}\), expressing the result as a single fraction. [4]

\begin{enumerate}[label=(\alph*)]
\item Express $\frac{1}{(2r-1)(2r+1)}$ in partial fractions. [3]

\item Hence find $\sum_{r=1}^{n}\frac{1}{(2r-1)(2r+1)}$, expressing the result as a single fraction. [4]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS FM Pure 2022 Q1 [7]}}