Moderate -0.8 This is a straightforward differentiation and tangent line question requiring only basic calculus techniques: differentiate a polynomial, substitute x=2 to find the gradient, then use y-y₁=m(x-x₁). It's simpler than average A-level questions as it involves no problem-solving or conceptual challenges, just routine application of standard methods.
A curve has equation
$$y = 2x^3 - 4x + 5$$
Find the equation of the tangent to the curve at the point \(P(2, 13)\).
Write your answer in the form \(y = mx + c\), where \(m\) and \(c\) are integers to be found.
Solutions relying on calculator technology are not acceptable.
[5]
A curve has equation
$$y = 2x^3 - 4x + 5$$
Find the equation of the tangent to the curve at the point $P(2, 13)$.
Write your answer in the form $y = mx + c$, where $m$ and $c$ are integers to be found.
Solutions relying on calculator technology are not acceptable.
[5]
\hfill \mbox{\textit{SPS SPS SM Pure 2021 Q1 [5]}}