SPS SPS SM Pure 2021 June — Question 3 5 marks

Exam BoardSPS
ModuleSPS SM Pure (SPS SM Pure)
Year2021
SessionJune
Marks5
TopicRadians, Arc Length and Sector Area
TypeCompound shape area
DifficultyModerate -0.8 This is a straightforward application of standard arc length and sector area formulas. Part (a) uses s=rθ directly to find OD, then part (b) uses the sector area formula after finding OB and angle AOB. Both parts require only routine recall and simple arithmetic with no problem-solving insight needed.
Spec1.05d Radians: arc length s=r*theta and sector area A=1/2 r^2 theta

\includegraphics{figure_1} The shape \(ABCDOA\), as shown in Figure 1, consists of a sector \(COD\) of a circle centre \(O\) joined to a sector \(AOB\) of a different circle, also centre \(O\). Given that arc length \(CD = 3\) cm, \(\angle COD = 0.4\) radians and \(AOD\) is a straight line of length 12 cm,
  1. find the length of \(OD\), [2]
  2. find the area of the shaded sector \(AOB\). [3]

\includegraphics{figure_1}

The shape $ABCDOA$, as shown in Figure 1, consists of a sector $COD$ of a circle centre $O$ joined to a sector $AOB$ of a different circle, also centre $O$.

Given that arc length $CD = 3$ cm, $\angle COD = 0.4$ radians and $AOD$ is a straight line of length 12 cm,

\begin{enumerate}[label=(\alph*)]
\item find the length of $OD$, [2]
\item find the area of the shaded sector $AOB$. [3]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS SM Pure 2021 Q3 [5]}}