SPS SPS SM Pure 2021 June — Question 9 7 marks

Exam BoardSPS
ModuleSPS SM Pure (SPS SM Pure)
Year2021
SessionJune
Marks7
TopicFunction Transformations
TypeStationary points after transformation
DifficultyStandard +0.3 This question involves routine trigonometric concepts: identifying minimum points of a cosine function (part a), applying horizontal stretches and translations (part b), and solving a trigonometric equation by converting to a single function (part c). While part (c) requires algebraic manipulation and calculator work across a specified range, all techniques are standard A-level fare with no novel problem-solving required. The 7 total marks and straightforward structure place this slightly easier than average.
Spec1.02w Graph transformations: simple transformations of f(x)1.05o Trigonometric equations: solve in given intervals

\includegraphics{figure_3} Figure 3 shows part of the curve with equation \(y = 3\cos x^2\). The point \(P(c, d)\) is a minimum point on the curve with \(c\) being the smallest negative value of \(x\) at which a minimum occurs.
  1. State the value of \(c\) and the value of \(d\). [1]
  2. State the coordinates of the point to which \(P\) is mapped by the transformation which transforms the curve with equation \(y = 3\cos x^2\) to the curve with equation
    1. \(y = 3\cos\left(\frac{x^2}{4}\right)\)
    2. \(y = 3\cos(x - 36)^2\)
    [2]
  3. Solve, for \(450° \leq \theta < 720°\), $$3\cos\theta = 8\tan\theta$$ giving your solution to one decimal place. [4]

\includegraphics{figure_3}

Figure 3 shows part of the curve with equation $y = 3\cos x^2$.

The point $P(c, d)$ is a minimum point on the curve with $c$ being the smallest negative value of $x$ at which a minimum occurs.

\begin{enumerate}[label=(\alph*)]
\item State the value of $c$ and the value of $d$. [1]
\item State the coordinates of the point to which $P$ is mapped by the transformation which transforms the curve with equation $y = 3\cos x^2$ to the curve with equation
\begin{enumerate}[label=(\roman*)]
\item $y = 3\cos\left(\frac{x^2}{4}\right)$
\item $y = 3\cos(x - 36)^2$
\end{enumerate}
[2]
\item Solve, for $450° \leq \theta < 720°$,
$$3\cos\theta = 8\tan\theta$$
giving your solution to one decimal place. [4]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS SM Pure 2021 Q9 [7]}}