AQA Further Paper 2 2024 June — Question 15 7 marks

Exam BoardAQA
ModuleFurther Paper 2 (Further Paper 2)
Year2024
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicInequalities
TypeSolve absolute value inequality
DifficultyStandard +0.8 This question requires sketching a modulus function involving a quadratic (requiring identification of roots at 0 and 4, vertex at 2, and reflection of negative portions), then solving a modulus inequality by considering cases and solving resulting quadratics. While systematic, it demands careful case analysis, algebraic manipulation of quadratics, and geometric interpretation—more demanding than standard A-level but not requiring deep novel insight.
Spec1.02l Modulus function: notation, relations, equations and inequalities1.02s Modulus graphs: sketch graph of |ax+b|1.02t Solve modulus equations: graphically with modulus function

The diagram shows the line \(y = 5 - x\) \includegraphics{figure_15}
  1. On the diagram above, sketch the graph of \(y = |x^2 - 4x|\), including all parts of the graph where it intersects the line \(y = 5 - x\) (You do not need to show the coordinates of the points of intersection.) [3 marks]
  2. Find the solution of the inequality $$|x^2 - 4x| > 5 - x$$ Give your answer in an exact form. [4 marks]

Question 15:

AnswerMarks
15(a)Draws curve with basically
correct shape and no negative
AnswerMarks Guidance
y-values.1.1b B1
Their graph intersects line at
AnswerMarks Guidance
four distinct points.1.1b B1
Value of 4 shown at x-intercept1.1b B1
Subtotal3
QMarking
instructionsAO Marks

AnswerMarks
15(b)Uses the modulus
function to obtain
two separate
quadratic
AnswerMarks Guidance
equations.3.1a M1
x2 – 3x – 5 = 0
3± 29
x =
2
4x – x2 = 5 – x
0 = x2 – 5x + 5
5± 5
x =
2
3– 29 5– 5 5+ 5 3+ 29
x < , < x < ,x>
2 2 2 2
Obtains four
correct x-values of
points of
intersection
(condone decimal
AnswerMarks Guidance
approximations).1.1a A1
Uses their graph to
obtain at least one
subset of the
solution set
(condone decimal
AnswerMarks Guidance
approximations).2.2a M1
Deduces a
completely correct
solution set with
AnswerMarks Guidance
exact values.2.2a A1
Subtotal4
Question total7
QMarking Instructions AO
Question 15:
--- 15(a) ---
15(a) | Draws curve with basically
correct shape and no negative
y-values. | 1.1b | B1
Their graph intersects line at
four distinct points. | 1.1b | B1
Value of 4 shown at x-intercept | 1.1b | B1
Subtotal | 3
Q | Marking
instructions | AO | Marks | Typical solution
--- 15(b) ---
15(b) | Uses the modulus
function to obtain
two separate
quadratic
equations. | 3.1a | M1 | x2 – 4x = 5 – x
x2 – 3x – 5 = 0
3± 29
x =
2
4x – x2 = 5 – x
0 = x2 – 5x + 5
5± 5
x =
2
3– 29 5– 5 5+ 5 3+ 29
x < , < x < ,x>
2 2 2 2
Obtains four
correct x-values of
points of
intersection
(condone decimal
approximations). | 1.1a | A1
Uses their graph to
obtain at least one
subset of the
solution set
(condone decimal
approximations). | 2.2a | M1
Deduces a
completely correct
solution set with
exact values. | 2.2a | A1
Subtotal | 4
Question total | 7
Q | Marking Instructions | AO | Marks | Typical Solution
The diagram shows the line $y = 5 - x$

\includegraphics{figure_15}

\begin{enumerate}[label=(\alph*)]
\item On the diagram above, sketch the graph of $y = |x^2 - 4x|$, including all parts of the graph where it intersects the line $y = 5 - x$

(You do not need to show the coordinates of the points of intersection.)
[3 marks]

\item Find the solution of the inequality
$$|x^2 - 4x| > 5 - x$$

Give your answer in an exact form.
[4 marks]
\end{enumerate}

\hfill \mbox{\textit{AQA Further Paper 2 2024 Q15 [7]}}