AQA Further Paper 2 2024 June — Question 1 1 marks

Exam BoardAQA
ModuleFurther Paper 2 (Further Paper 2)
Year2024
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVector Product and Surfaces
TypeConditions for vector product to be zero
DifficultyEasy -1.8 This is a straightforward 1-mark question testing basic recall of the vector cross product formula. Students simply need to compute the cross product, set it equal to the zero vector, and solve for λ from any component equation. It's a routine calculation with no problem-solving required, and the multiple-choice format makes it even more accessible. Despite being from Further Maths, this is significantly easier than average A-level questions.
Spec4.04g Vector product: a x b perpendicular vector

It is given that $$\begin{bmatrix} 2 \\ 1 \\ 9 \end{bmatrix} \times \begin{bmatrix} 5 \\ \lambda \\ -6 \end{bmatrix} = 0$$ where \(\lambda\) is a constant. Find the value of \(\lambda\) Circle your answer. [1 mark] \(-28\) \quad\quad \(-8\) \quad\quad \(8\) \quad\quad \(28\)

Question 1:
AnswerMarks Guidance
1Circles 3rd answer 1.1b
Question total1
QMarking instructions AO
Question 1:
1 | Circles 3rd answer | 1.1b | B1 | 8
Question total | 1
Q | Marking instructions | AO | Marks | Typical solution
It is given that
$$\begin{bmatrix} 2 \\ 1 \\ 9 \end{bmatrix} \times \begin{bmatrix} 5 \\ \lambda \\ -6 \end{bmatrix} = 0$$

where $\lambda$ is a constant.

Find the value of $\lambda$

Circle your answer.
[1 mark]

$-28$ \quad\quad $-8$ \quad\quad $8$ \quad\quad $28$

\hfill \mbox{\textit{AQA Further Paper 2 2024 Q1 [1]}}