AQA Paper 3 2020 June — Question 6 7 marks

Exam BoardAQA
ModulePaper 3 (Paper 3)
Year2020
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFunction Transformations
TypeMultiple separate transformations (sketch-based, modulus involved)
DifficultyModerate -0.3 This is a standard graph transformations question testing reflection, vertical stretch/translation, and derivative sketching. While it requires understanding of multiple concepts, these are routine A-level techniques with no problem-solving or novel insight required. The 7 marks suggest straightforward application across three parts, making it slightly easier than average.
Spec1.02w Graph transformations: simple transformations of f(x)1.07c Sketch gradient function: for given curve

The graph of \(y = f(x)\) is shown below. \includegraphics{figure_6}
  1. Sketch the graph of \(y = f(-x)\) [2 marks]
  2. Sketch the graph of \(y = 2f(x) - 4\) [2 marks]
  3. Sketch the graph of \(y = f'(x)\) [3 marks]

Question 6:

AnswerMarks Guidance
6(a)Sketches correct shape with
graph reflected in the y-axis1.1a M1
Labels all four points correctly
AnswerMarks Guidance
Condone omission of (0, 2)1.1b A1

AnswerMarks
6(b)Calculates or labels at least two
points of (2, 8), (0, 0), (-1, -4) or
AnswerMarks Guidance
(-2, -8) correctly3.1a M1
Sketches correct graph and
labels all four points correctly
Condone omission of (0,0) or
AnswerMarks Guidance
(-1, -4) or both1.1b A1

AnswerMarks
6(c)Calculates or obtains gradient 2
for between x = -2 and x = 2
PI by line y = 2
or
calculates or obtains gradient 0
when x < -2 or when x > 2
PI by explaining gradient when
x < -2 or x > 2 is zero or by
drawing visible solid horizontal
AnswerMarks Guidance
lines on the x axis1.1b B1
Draws a horizontal line on the
positive y-axis between
x = -2 and x = 2 without
extension
AnswerMarks Guidance
Ignore any other lines if drawn1.1a M1
Draws correct two solid
horizontal lines on the x-axis
up to (−2, 0) and from (2, 0) and
their horizontal line y = 2
between x = -2 and x = 2
Accept explanation that gradient
for x < -2 and x > 2 is zero if no
solid horizontal lines are drawn
on the x-axis
Do not accept solid vertical lines
at x = -2 or x = 2
Follow through their value of
AnswerMarks Guidance
positive gradient1.1b A1F
Total7
QMarking instructions AO
Question 6:
--- 6(a) ---
6(a) | Sketches correct shape with
graph reflected in the y-axis | 1.1a | M1
Labels all four points correctly
Condone omission of (0, 2) | 1.1b | A1
--- 6(b) ---
6(b) | Calculates or labels at least two
points of (2, 8), (0, 0), (-1, -4) or
(-2, -8) correctly | 3.1a | M1
Sketches correct graph and
labels all four points correctly
Condone omission of (0,0) or
(-1, -4) or both | 1.1b | A1
--- 6(c) ---
6(c) | Calculates or obtains gradient 2
for between x = -2 and x = 2
PI by line y = 2
or
calculates or obtains gradient 0
when x < -2 or when x > 2
PI by explaining gradient when
x < -2 or x > 2 is zero or by
drawing visible solid horizontal
lines on the x axis | 1.1b | B1
Draws a horizontal line on the
positive y-axis between
x = -2 and x = 2 without
extension
Ignore any other lines if drawn | 1.1a | M1
Draws correct two solid
horizontal lines on the x-axis
up to (−2, 0) and from (2, 0) and
their horizontal line y = 2
between x = -2 and x = 2
Accept explanation that gradient
for x < -2 and x > 2 is zero if no
solid horizontal lines are drawn
on the x-axis
Do not accept solid vertical lines
at x = -2 or x = 2
Follow through their value of
positive gradient | 1.1b | A1F
Total | 7
Q | Marking instructions | AO | Marks | Typical solution
The graph of $y = f(x)$ is shown below.

\includegraphics{figure_6}

\begin{enumerate}[label=(\alph*)]
\item Sketch the graph of $y = f(-x)$
[2 marks]

\item Sketch the graph of $y = 2f(x) - 4$
[2 marks]

\item Sketch the graph of $y = f'(x)$
[3 marks]
\end{enumerate}

\hfill \mbox{\textit{AQA Paper 3 2020 Q6 [7]}}