AQA Paper 3 2020 June — Question 1 1 marks

Exam BoardAQA
ModulePaper 3 (Paper 3)
Year2020
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndefinite & Definite Integrals
TypePure definite integration
DifficultyEasy -1.8 This is a trivial 1-mark question testing only the basic linearity property of integration: ∫(f(x)+1)dx = ∫f(x)dx + ∫1dx = 7 + 10 = 17. Requires no problem-solving, just direct application of a fundamental rule with simple arithmetic.
Spec1.08d Evaluate definite integrals: between limits

Given that $$\int_0^{10} f(x) \, dx = 7$$ deduce the value of $$\int_0^{10} \left( f(x) + 1 \right) dx$$ Circle your answer. [1 mark] \(-3\) \quad \(7\) \quad \(8\) \quad \(17\)

Question 1:
AnswerMarks Guidance
1Circles correct answer 2.2a
Total1
QMarking instructions AO
Question 1:
1 | Circles correct answer | 2.2a | B1 | 17
Total | 1
Q | Marking instructions | AO | Marks | Typical solution
Given that
$$\int_0^{10} f(x) \, dx = 7$$

deduce the value of
$$\int_0^{10} \left( f(x) + 1 \right) dx$$

Circle your answer.
[1 mark]

$-3$ \quad $7$ \quad $8$ \quad $17$

\hfill \mbox{\textit{AQA Paper 3 2020 Q1 [1]}}