AQA Paper 3 2020 June — Question 2 1 marks

Exam BoardAQA
ModulePaper 3 (Paper 3)
Year2020
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHarmonic Form
TypeExpress in harmonic form
DifficultyEasy -1.2 This is a straightforward application of the R-cos(θ+α) formula where R = √(a²+b²) = √(36+64) = 10. It's a 1-mark multiple-choice question requiring only direct recall of a standard formula with no problem-solving or multi-step reasoning, making it easier than average.
Spec1.05n Harmonic form: a sin(x)+b cos(x) = R sin(x+alpha) etc

Given that $$6 \cos \theta + 8 \sin \theta \equiv R \cos (\theta + \alpha)$$ find the value of \(R\). Circle your answer. [1 mark] \(6\) \quad \(8\) \quad \(10\) \quad \(14\)

Question 2:
AnswerMarks Guidance
2Circles correct answer 1.1b
Total1
QMarking instructions AO
Question 2:
2 | Circles correct answer | 1.1b | B1 | 10
Total | 1
Q | Marking instructions | AO | Marks | Typical solution
Given that
$$6 \cos \theta + 8 \sin \theta \equiv R \cos (\theta + \alpha)$$

find the value of $R$.

Circle your answer.
[1 mark]

$6$ \quad $8$ \quad $10$ \quad $14$

\hfill \mbox{\textit{AQA Paper 3 2020 Q2 [1]}}