| Exam Board | AQA |
|---|---|
| Module | Paper 2 (Paper 2) |
| Year | 2024 |
| Session | June |
| Marks | 3 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Constant acceleration (SUVAT) |
| Type | Displacement expressions and comparison |
| Difficulty | Moderate -0.8 Part (a) is direct substitution requiring only arithmetic. Part (b) requires solving a quadratic inequality, which is a standard technique, but the question is straightforward with no conceptual challenges—the quadratic factorises easily and students simply need to identify when 6t - 2t² > 0. This is easier than average A-level content. |
| Spec | 1.02g Inequalities: linear and quadratic in single variable3.02a Kinematics language: position, displacement, velocity, acceleration |
| Answer | Marks | Guidance |
|---|---|---|
| 14(a) | Obtains – 8 | 1.1b |
| Subtotal | 1 | |
| Q | Marking instructions | AO |
| Answer | Marks |
|---|---|
| 14(b) | Forms an equation or inequality |
| Answer | Marks | Guidance |
|---|---|---|
| t = 0 and t = 3 | 3.1a | M1 |
| Answer | Marks | Guidance |
|---|---|---|
| Obtains OE | 1.1b | A1 |
| Subtotal | 2 | |
| Question 14 Total | 3 | |
| Q | Marking instructions | AO |
Question 14:
--- 14(a) ---
14(a) | Obtains – 8 | 1.1b | B1 | –8
Subtotal | 1
Q | Marking instructions | AO | Marks | Typical solution
--- 14(b) ---
14(b) | Forms an equation or inequality
to compare 6t−2t2 with 0
PI by 6t =2t2, 6t >2t2 or
t = 0 and t = 3 | 3.1a | M1 | −2t2 +6t >0
0<t <3
So
0<t <3
Obtains OE | 1.1b | A1
Subtotal | 2
Question 14 Total | 3
Q | Marking instructions | AO | Marks | Typical solutionThe displacement, $r$ metres, of a particle at time $t$ seconds is
$$r = 6t - 2t^2$$
\begin{enumerate}[label=(\alph*)]
\item Find the value of $r$ when $t = 4$
[1 mark]
\item Determine the range of values of $t$ for which the displacement is positive.
[2 marks]
\end{enumerate}
\hfill \mbox{\textit{AQA Paper 2 2024 Q14 [3]}}