Easy -2.0 This is a straightforward application of Newton's second law (F=ma) with net force 10-4=6N and mass 2kg giving a=3ms⁻². It's a single-step calculation with multiple choice answers, requiring only basic recall of F=ma with no problem-solving or conceptual challenge.
Two constant forces act on a particle, of mass 2 kilograms, so that it moves forward in a straight line.
The two forces are:
• a forward driving force of 10 newtons
• a resistance force of 4 newtons.
Find the acceleration of the particle.
Circle your answer.
[1 mark]
\(2 \text{ m s}^{-2}\) \(\quad\) \(3 \text{ m s}^{-2}\) \(\quad\) \(5 \text{ m s}^{-2}\) \(\quad\) \(12 \text{ m s}^{-2}\)
Two constant forces act on a particle, of mass 2 kilograms, so that it moves forward in a straight line.
The two forces are:
• a forward driving force of 10 newtons
• a resistance force of 4 newtons.
Find the acceleration of the particle.
Circle your answer.
[1 mark]
$2 \text{ m s}^{-2}$ $\quad$ $3 \text{ m s}^{-2}$ $\quad$ $5 \text{ m s}^{-2}$ $\quad$ $12 \text{ m s}^{-2}$
\hfill \mbox{\textit{AQA Paper 2 2024 Q12 [1]}}