| Exam Board | AQA |
|---|---|
| Module | Paper 2 (Paper 2) |
| Year | 2018 |
| Session | June |
| Marks | 9 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Variable acceleration (1D) |
| Type | Variable acceleration with initial conditions |
| Difficulty | Standard +0.8 This question requires integrating acceleration twice to find displacement, then solving a non-standard equation (involving t^4 and t^5 terms) numerically. While the setup is straightforward mechanics, solving these equations requires either iterative methods or calculator techniques beyond routine A-level procedures, and part (c) tests conceptual understanding of mathematical modelling assumptions. |
| Spec | 3.02d Constant acceleration: SUVAT formulae3.02f Non-uniform acceleration: using differentiation and integration |
| Answer | Marks | Guidance |
|---|---|---|
| 15(a) | Integrates 0.138 (cid:1872)(cid:2870) twice | AO3.4 |
| Answer | Marks | Guidance |
|---|---|---|
| consideration of c | AO1.1b | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| of integration is zero | AO1.1b | B1 |
| Finds the correct time for minibus A | AO1.1b | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| 15(b) | Integrates 0.024 (cid:1872)(cid:2871) twice | AO1.1a |
| Answer | Marks | Guidance |
|---|---|---|
| consideration of c | AO1.1b | A1 |
| Finds correct time for minibus B | AO1.1b | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| parts | AO3.2a | E1F |
| Answer | Marks | Guidance |
|---|---|---|
| 15(c) | Explains how reaction times of each | |
| driver could change the outcome | AO3.5b | E1 |
| Answer | Marks | Guidance |
|---|---|---|
| Total | 9 | |
| Q | Marking Instructions | AO |
Question 15:
--- 15(a) ---
15(a) | Integrates 0.138 (cid:1872)(cid:2870) twice | AO3.4 | M1 | v0.138t2dt
0.046t3 c
t 0,v0c0
s 0.046t3dt
0.0115t4 k
t 0,s0k 0
0.0115t4 100
t 9.657
Finds the correct expression for
displacement condone no
consideration of c | AO1.1b | A1
Demonstrates at least one constant
of integration is zero | AO1.1b | B1
Finds the correct time for minibus A | AO1.1b | A1
--- 15(b) ---
15(b) | Integrates 0.024 (cid:1872)(cid:2871) twice | AO1.1a | M1 | v0.024t3dt
0.006t4 c
t 0,v0c0
s 0.006t4dt
0.0012t5 k
t 0,s0k 0
0.0012 (cid:1872)(cid:2873) (cid:3404) 100
t 9.642
9.642 < 9.657
company chooses minibus B
Finds the correct expression for
displacement condone no
consideration of c | AO1.1b | A1
Finds correct time for minibus B | AO1.1b | A1
States correct choice consistent with
‘their’ answers
Must have integrated twice in both
parts | AO3.2a | E1F
--- 15(c) ---
15(c) | Explains how reaction times of each
driver could change the outcome | AO3.5b | E1 | If Driver B’s reaction time is greater
than Driver A’s then A could travel
100 metres faster than B
Total | 9
Q | Marking Instructions | AO | Marks | Typical Solution
A driver is road-testing two minibuses, A and B, for a taxi company.
The performance of each minibus along a straight track is compared.
A flag is dropped to indicate the start of the test.
Each minibus starts from rest.
The acceleration in m s$^{-2}$ of each minibus is modelled as a function of time, $t$ seconds, after the flag is dropped:
The acceleration of A = $0.138 t^2$
The acceleration of B = $0.024 t^3$
\begin{enumerate}[label=(\alph*)]
\item Find the time taken for A to travel 100 metres.
Give your answer to four significant figures.
[4 marks]
\item The company decides to buy the minibus which travels 100 metres in the shortest time.
Determine which minibus should be bought.
[4 marks]
\item The models assume that both minibuses start moving immediately when $t = 0$
In light of this, explain why the company may, in reality, make the wrong decision.
[1 mark]
\end{enumerate}
\hfill \mbox{\textit{AQA Paper 2 2018 Q15 [9]}}