A market trader notices that daily sales are dependent on two variables:
number of hours, \(t\), after the stall opens
total sales, \(x\), in pounds since the stall opened.
The trader models the rate of sales as directly proportional to \(\frac{8 - t}{x}\)
After two hours the rate of sales is £72 per hour and total sales are £336
- Show that
$$x \frac{dx}{dt} = 4032(8 - t)$$
[3 marks]
- Hence, show that
$$x^2 = 4032t(16 - t)$$
[3 marks]
- The stall opens at 09.30.
- The trader closes the stall when the rate of sales falls below £24 per hour.
Using the results in parts (a) and (b), calculate the earliest time that the trader closes the stall.
[6 marks]
- Explain why the model used by the trader is not valid at 09.30.
[2 marks]