Easy -1.8 This is a straightforward one-mark moments question requiring only the principle that clockwise moments equal anticlockwise moments about the pivot. Students simply calculate 4×0.6 = 1.5×x and solve for x = 1.6m. It's a routine recall exercise with minimal calculation and no problem-solving required, making it significantly easier than average A-level questions.
A uniform rod, AB, has length 4 metres.
The rod is resting on a support at its midpoint C.
A particle of mass 4 kg is placed 0.6 metres to the left of C.
Another particle of mass 1.5 kg is placed \(x\) metres to the right of C, as shown.
\includegraphics{figure_3}
The rod is balanced in equilibrium at C.
Find \(x\).
Circle your answer.
[1 mark]
1.8 m 1.5 m 1.75 m 1.6 m
A uniform rod, AB, has length 4 metres.
The rod is resting on a support at its midpoint C.
A particle of mass 4 kg is placed 0.6 metres to the left of C.
Another particle of mass 1.5 kg is placed $x$ metres to the right of C, as shown.
\includegraphics{figure_3}
The rod is balanced in equilibrium at C.
Find $x$.
Circle your answer.
[1 mark]
1.8 m 1.5 m 1.75 m 1.6 m
\hfill \mbox{\textit{AQA Paper 2 2018 Q11 [1]}}