AQA Paper 2 2018 June — Question 10 1 marks

Exam BoardAQA
ModulePaper 2 (Paper 2)
Year2018
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicConstant acceleration (SUVAT)
DifficultyEasy -2.0 This is a trivial one-mark question requiring only the formula a = (v-u)/t with straightforward substitution (1.28/1.8 ≈ 0.71 cm/s² = 0.0071 m/s²). The multiple choice format and unit conversion are the only potential pitfalls, but this is far below average A-level difficulty—essentially testing basic recall of a single kinematics formula.
Spec3.02d Constant acceleration: SUVAT formulae

A garden snail moves in a straight line from rest to 1.28 cm s\(^{-1}\), with a constant acceleration in 1.8 seconds. Find the acceleration of the snail. Circle your answer. [1 mark] 2.30 m s\(^{-2}\) 0.71 m s\(^{-2}\) 0.0071 m s\(^{-2}\) 0.023 m s\(^{-2}\)

Question 10:
AnswerMarks Guidance
10Circles correct answer AO1.1b
Total1
QMarking Instructions AO
Question 10:
10 | Circles correct answer | AO1.1b | B1 | 0.0071 m s-2
Total | 1
Q | Marking Instructions | AO | Marks | Typical Solution
A garden snail moves in a straight line from rest to 1.28 cm s$^{-1}$, with a constant acceleration in 1.8 seconds.

Find the acceleration of the snail.

Circle your answer.
[1 mark]

2.30 m s$^{-2}$        0.71 m s$^{-2}$        0.0071 m s$^{-2}$        0.023 m s$^{-2}$

\hfill \mbox{\textit{AQA Paper 2 2018 Q10 [1]}}