AQA Paper 1 2019 June — Question 9 5 marks

Exam BoardAQA
ModulePaper 1 (Paper 1)
Year2019
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProof
TypeRational and irrational number properties
DifficultyStandard +0.8 This is a proof by contradiction requiring students to understand the definition of rational numbers and apply logical reasoning. While the proof structure is standard (assume the sum is rational, derive a contradiction), it requires formal mathematical thinking beyond routine calculation, making it moderately challenging for A-level students who may have limited experience with proof writing.
Spec1.01a Proof: structure of mathematical proof and logical steps1.01d Proof by contradiction

Prove that the sum of a rational number and an irrational number is always irrational. [5 marks]

Question 9:
AnswerMarks
9Begins proof by contradiction.
This may be evidenced by: stating
assumption at the start “the sum is
rational”
Or
Sight of “contradiction” later as part
AnswerMarks Guidance
of argument.3.1a M1
irrational and their sum is rational.
Then
a c
+n=
b d
Where a, b, c and d are all
integers.
c a
n= −
d b
bc−ad
=
bd
∴n is rational, which is a
contradiction.
So the original statement is false
and the sum of a rational and
irrational must be irrational.
Forms an equation of the form
rational + irrational = rational with
the rationals written algebraically
a c
+n=
b d
n must clearly be irrational and not
written as an algebraic fraction and
AnswerMarks Guidance
not a specific value.2.5 M1
Manipulates their equation to show
AnswerMarks Guidance
that n is rational1.1b A1
Explains or demonstrates why
AnswerMarks Guidance
there is a contradiction2.4 E1
Completes rigorous argument to
prove the required result including
correct initial assumptions
Where a, b, c and d are all
AnswerMarks Guidance
integers.2.1 R1
Total5
QMarking instructions AO
Question 9:
9 | Begins proof by contradiction.
This may be evidenced by: stating
assumption at the start “the sum is
rational”
Or
Sight of “contradiction” later as part
of argument. | 3.1a | M1 | Assume m is rational and n is
irrational and their sum is rational.
Then
a c
+n=
b d
Where a, b, c and d are all
integers.
c a
n= −
d b
bc−ad
=
bd
∴n is rational, which is a
contradiction.
So the original statement is false
and the sum of a rational and
irrational must be irrational.
Forms an equation of the form
rational + irrational = rational with
the rationals written algebraically
a c
+n=
b d
n must clearly be irrational and not
written as an algebraic fraction and
not a specific value. | 2.5 | M1
Manipulates their equation to show
that n is rational | 1.1b | A1
Explains or demonstrates why
there is a contradiction | 2.4 | E1
Completes rigorous argument to
prove the required result including
correct initial assumptions
Where a, b, c and d are all
integers. | 2.1 | R1
Total | 5
Q | Marking instructions | AO | Mark | Typical solution
Prove that the sum of a rational number and an irrational number is always irrational.
[5 marks]

\hfill \mbox{\textit{AQA Paper 1 2019 Q9 [5]}}