AQA Paper 1 2019 June — Question 2 1 marks

Exam BoardAQA
ModulePaper 1 (Paper 1)
Year2019
SessionJune
Marks1
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Mark schemeDownload PDF ↗
TopicDifferentiating Transcendental Functions
TypeDifferentiate exponential functions
DifficultyEasy -1.8 This is a direct application of the chain rule for differentiating e^(kx), which is a standard result students memorize. It's a 1-mark multiple-choice question requiring only recall of a basic differentiation formula with no problem-solving or multi-step reasoning needed.
Spec1.07j Differentiate exponentials: e^(kx) and a^(kx)
Given \(y = e^{kx}\), where \(k\) is a constant, find \(\frac{dy}{dx}\) Circle your answer. [1 mark] $$\frac{dy}{dx} = e^{kx} \quad \frac{dy}{dx} = ke^{kx} \quad \frac{dy}{dx} = kxe^{x-1} \quad \frac{dy}{dx} = \frac{e^{kx}}{k}$$
Question 2:
AnswerMarks Guidance
2Circles the correct response 1.1b
=kekx
dx
AnswerMarks Guidance
Total1
QMarking instructions AO 
Question 2:
2 | Circles the correct response | 1.1b | B1 | dy
=kekx
dx
Total | 1
Q | Marking instructions | AO | Mark | Typical solution
Given $y = e^{kx}$, where $k$ is a constant, find $\frac{dy}{dx}$

Circle your answer.
[1 mark]

$$\frac{dy}{dx} = e^{kx} \quad \frac{dy}{dx} = ke^{kx} \quad \frac{dy}{dx} = kxe^{x-1} \quad \frac{dy}{dx} = \frac{e^{kx}}{k}$$

\hfill \mbox{\textit{AQA Paper 1 2019 Q2 [1]}}
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Q1 1 Q2 1 Q3 1 Q4 4 Q5 7 Q6 8 Q7 11 Q8 4 Q9 5 Q10 4 Q11 4 Q12 7 Q13 7 Q14 10 Q15 13 Q16 16