Easy -1.8 This is a straightforward application of Newton's second law (F=ma) requiring only one step: 5 × 0.6 = 3, so F - R = 3. It's a 1-mark multiple choice question testing basic recall of a fundamental formula with no problem-solving or conceptual challenge required.
An object of mass \(5\,\mathrm{kg}\) is moving in a straight line.
As a result of experiencing a forward force of \(F\) newtons and a resistant force of \(R\) newtons it accelerates at \(0.6\,\mathrm{m}\,\mathrm{s}^{-2}\)
Which one of the following equations is correct?
Circle your answer.
[1 mark]
\(F - R = 0\) \quad \(F - R = 5\) \quad \(F - R = 3\) \quad \(F - R = 0.6\)
An object of mass $5\,\mathrm{kg}$ is moving in a straight line.
As a result of experiencing a forward force of $F$ newtons and a resistant force of $R$ newtons it accelerates at $0.6\,\mathrm{m}\,\mathrm{s}^{-2}$
Which one of the following equations is correct?
Circle your answer.
[1 mark]
$F - R = 0$ \quad $F - R = 5$ \quad $F - R = 3$ \quad $F - R = 0.6$
\hfill \mbox{\textit{AQA AS Paper 1 2018 Q12 [1]}}