Easy -1.2 This is a straightforward 1-mark multiple choice question requiring only the basic technique of finding the gradient of a radius and taking the negative reciprocal. The origin lies on the circle (easily verified), the centre is clearly (2,-3), so the radius gradient is -3/2 and the tangent gradient is 2/3. No problem-solving or extended reasoning required—pure routine application.
A circle has equation \((x - 2)^2 + (y + 3)^2 = 13\)
Find the gradient of the tangent to this circle at the origin.
Circle your answer.
[1 mark]
\(-\frac{3}{2}\) \quad \(-\frac{2}{3}\) \quad \(\frac{2}{3}\) \quad \(\frac{3}{2}\)
A circle has equation $(x - 2)^2 + (y + 3)^2 = 13$
Find the gradient of the tangent to this circle at the origin.
Circle your answer.
[1 mark]
$-\frac{3}{2}$ \quad $-\frac{2}{3}$ \quad $\frac{2}{3}$ \quad $\frac{3}{2}$
\hfill \mbox{\textit{AQA AS Paper 1 2018 Q2 [1]}}