AQA AS Paper 1 2018 June — Question 11 1 marks

Exam BoardAQA
ModuleAS Paper 1 (AS Paper 1)
Year2018
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicConstant acceleration (SUVAT)
TypeVertical motion under gravity
DifficultyEasy -2.0 This is a straightforward application of a single SUVAT equation (v² = u² + 2as) with all values given directly. It's a 1-mark multiple-choice question requiring only substitution into a standard formula with no problem-solving or conceptual challenge, making it significantly easier than average A-level questions.
Spec3.02d Constant acceleration: SUVAT formulae

In this question use \(g = 9.8\,\mathrm{m}\,\mathrm{s}^{-2}\) A ball, initially at rest, is dropped from a height of \(40\,\mathrm{m}\) above the ground. Calculate the speed of the ball when it reaches the ground. Circle your answer. [1 mark] \(-28\,\mathrm{m}\,\mathrm{s}^{-1}\) \quad \(28\,\mathrm{m}\,\mathrm{s}^{-1}\) \quad \(-780\,\mathrm{m}\,\mathrm{s}^{-1}\) \quad \(780\,\mathrm{m}\,\mathrm{s}^{-1}\)

Question 11:
AnswerMarks Guidance
11Circles correct answer AO1.1b
Total1
QMarking Instructions AO
Question 11:
11 | Circles correct answer | AO1.1b | B1 | a = 28
Total | 1
Q | Marking Instructions | AO | Marks | Typical Solution
In this question use $g = 9.8\,\mathrm{m}\,\mathrm{s}^{-2}$

A ball, initially at rest, is dropped from a height of $40\,\mathrm{m}$ above the ground.

Calculate the speed of the ball when it reaches the ground.

Circle your answer.
[1 mark]

$-28\,\mathrm{m}\,\mathrm{s}^{-1}$ \quad $28\,\mathrm{m}\,\mathrm{s}^{-1}$ \quad $-780\,\mathrm{m}\,\mathrm{s}^{-1}$ \quad $780\,\mathrm{m}\,\mathrm{s}^{-1}$

\hfill \mbox{\textit{AQA AS Paper 1 2018 Q11 [1]}}