| Exam Board | OCR |
|---|---|
| Module | C3 (Core Mathematics 3) |
| Marks | 4 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Modulus function |
| Type | Solve |linear| = |linear| (both linear inside) |
| Difficulty | Moderate -0.3 This is a straightforward modulus equation requiring consideration of cases based on critical points at x=1/6 and x=1. Students need to solve two linear equations (when expressions have same/opposite signs), which is slightly below average difficulty as it's a standard technique with no conceptual surprises, though the case analysis requires care. |
| Spec | 1.02l Modulus function: notation, relations, equations and inequalities |
Find the exact solutions of the equation $|6x - 1| = |x - 1|$. [4]
\hfill \mbox{\textit{OCR C3 Q2 [4]}}