| Exam Board | OCR |
|---|---|
| Module | C3 (Core Mathematics 3) |
| Marks | 4 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Composite & Inverse Functions |
| Type | Evaluate composite at point |
| Difficulty | Moderate -0.8 This is a straightforward question on function composition with a simple quadratic. Part (i) requires recognizing that a negative squared term has maximum value 0, giving range f(x) ≤ 10. Part (ii) is routine substitution: f(-1) = 6, then f(6) = -29. Both parts are more basic than a typical C3 question, requiring only elementary function evaluation with no problem-solving insight. |
| Spec | 1.02u Functions: definition and vocabulary (domain, range, mapping) |
The function f is defined for all real values of $x$ by
$$f(x) = 10 - (x + 3)^2.$$
\begin{enumerate}[label=(\roman*)]
\item State the range of f. [1]
\item Find the value of ff(-1). [3]
\end{enumerate}
\hfill \mbox{\textit{OCR C3 Q1 [4]}}