OCR MEI C1 — Question 6 11 marks

Exam BoardOCR MEI
ModuleC1 (Core Mathematics 1)
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCurve Sketching
TypeSketch rational function from transformation
DifficultyModerate -0.3 This is a straightforward C1 transformation and algebraic question. Part (i) requires a standard horizontal translation of 1/x. Part (ii) is simple equation solving. Part (iii) involves forming and solving a quadratic, which is routine for C1, though presenting answers in surd form adds minor complexity. Overall slightly easier than average due to standard techniques throughout.
Spec1.02f Solve quadratic equations: including in a function of unknown1.02o Sketch reciprocal curves: y=a/x and y=a/x^21.02q Use intersection points: of graphs to solve equations1.02w Graph transformations: simple transformations of f(x)

  1. \includegraphics{figure_1} Fig. 10 shows a sketch of the graph of \(y = \frac{1}{x}\). Sketch the graph of \(y = \frac{1}{x-2}\), showing clearly the coordinates of any points where it crosses the axes. [3]
  2. Find the value of \(x\) for which \(\frac{1}{x-2} = 5\). [2]
  3. Find the \(x\)-coordinates of the points of intersection of the graphs of \(y = x\) and \(y = \frac{1}{x-2}\). Give your answers in the form \(a \pm \sqrt{b}\). Show the position of these points on your graph in part (i). [6]

Question 6:
AnswerMarks
6ii
iiicorrect graph with clear
asymptote x = 2 (though need not
be marked)
(0, − ½ ) shown
11/5 or 2.2 o.e. isw
1
x=
x−2
x(x − 2) = 1 o.e.
x2 − 2x − 1 [= 0]; ft their equiv
eqn
attempt at quadratic formula
1 ±√2 cao
AnswerMarks
position of points shownG2
G1
2
M1
M1
M1
M1
A1
AnswerMarks
B1G1 for one branch correct; condone
(0, − ½ ) not shown
SC1 for both sections of graph
shifted two to left
allow seen calculated
M1 for correct first step
or equivs with ys
or (x − 1)2 − 1 = 1 o.e.
or (x − 1) = ±√2 (condone one error)
on their curve with y = x (line drawn
or y = x indicated by both coords);
condone intent of diagonal line with
gradient approx 1through origin as y
AnswerMarks
= x if unlabelled3
2
6
Question 6:
6 | ii
iii | correct graph with clear
asymptote x = 2 (though need not
be marked)
(0, − ½ ) shown
11/5 or 2.2 o.e. isw
1
x=
x−2
x(x − 2) = 1 o.e.
x2 − 2x − 1 [= 0]; ft their equiv
eqn
attempt at quadratic formula
1 ±√2 cao
position of points shown | G2
G1
2
M1
M1
M1
M1
A1
B1 | G1 for one branch correct; condone
(0, − ½ ) not shown
SC1 for both sections of graph
shifted two to left
allow seen calculated
M1 for correct first step
or equivs with ys
or (x − 1)2 − 1 = 1 o.e.
or (x − 1) = ±√2 (condone one error)
on their curve with y = x (line drawn
or y = x indicated by both coords);
condone intent of diagonal line with
gradient approx 1through origin as y
= x if unlabelled | 3
2
6
\begin{enumerate}[label=(\roman*)]
\item \includegraphics{figure_1}

Fig. 10 shows a sketch of the graph of $y = \frac{1}{x}$.

Sketch the graph of $y = \frac{1}{x-2}$, showing clearly the coordinates of any points where it crosses the axes. [3]

\item Find the value of $x$ for which $\frac{1}{x-2} = 5$. [2]

\item Find the $x$-coordinates of the points of intersection of the graphs of $y = x$ and $y = \frac{1}{x-2}$. Give your answers in the form $a \pm \sqrt{b}$.

Show the position of these points on your graph in part (i). [6]
\end{enumerate}

\hfill \mbox{\textit{OCR MEI C1  Q6 [11]}}