Express \(x^2 - 6x + 2\) in the form \((x - a)^2 - b\). [3]
State the coordinates of the turning point on the graph of \(y = x^2 - 6x + 2\). [2]
Sketch the graph of \(y = x^2 - 6x + 2\). You need not state the coordinates of the points where the graph intersects the \(x\)-axis. [2]
Solve the simultaneous equations \(y = x^2 - 6x + 2\) and \(y = 2x - 14\). Hence show that the line \(y = 2x - 14\) is a tangent to the curve \(y = x^2 - 6x + 2\). [5]
\includegraphics{figure_1}
Fig. 10 shows a sketch of the graph of \(y = \frac{1}{x}\).
Sketch the graph of \(y = \frac{1}{x-2}\), showing clearly the coordinates of any points where it crosses the axes. [3]
Find the value of \(x\) for which \(\frac{1}{x-2} = 5\). [2]
Find the \(x\)-coordinates of the points of intersection of the graphs of \(y = x\) and \(y = \frac{1}{x-2}\). Give your answers in the form \(a \pm \sqrt{b}\).
Show the position of these points on your graph in part (i). [6]