CAIE P1 2015 June — Question 9 9 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2015
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors 3D & Lines
TypeAngle between two vectors/lines (direct)
DifficultyModerate -0.3 This is a straightforward multi-part vectors question requiring standard techniques: scalar product for angle (routine calculation), vector addition to find C, then magnitude calculations. All steps are textbook exercises with no novel insight needed, making it slightly easier than average for A-level.
Spec1.10c Magnitude and direction: of vectors1.10d Vector operations: addition and scalar multiplication1.10e Position vectors: and displacement

Relative to an origin \(O\), the position vectors of points \(A\) and \(B\) are given by $$\overrightarrow{OA} = 2\mathbf{i} + 4\mathbf{j} + 4\mathbf{k} \quad \text{and} \quad \overrightarrow{OB} = 3\mathbf{i} + \mathbf{j} + 4\mathbf{k}.$$
  1. Use a vector method to find angle \(AOB\). [4]
The point \(C\) is such that \(\overrightarrow{AB} = \overrightarrow{BC}\).
  1. Find the unit vector in the direction of \(\overrightarrow{OC}\). [4]
  2. Show that triangle \(OAC\) is isosceles. [1]

Relative to an origin $O$, the position vectors of points $A$ and $B$ are given by
$$\overrightarrow{OA} = 2\mathbf{i} + 4\mathbf{j} + 4\mathbf{k} \quad \text{and} \quad \overrightarrow{OB} = 3\mathbf{i} + \mathbf{j} + 4\mathbf{k}.$$

\begin{enumerate}[label=(\roman*)]
\item Use a vector method to find angle $AOB$. [4]
\end{enumerate}

The point $C$ is such that $\overrightarrow{AB} = \overrightarrow{BC}$.

\begin{enumerate}[label=(\roman*)]
\setcounter{enumi}{1}
\item Find the unit vector in the direction of $\overrightarrow{OC}$. [4]
\item Show that triangle $OAC$ is isosceles. [1]
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2015 Q9 [9]}}