Pre-U Pre-U 9794/1 2016 Specimen — Question 4 6 marks

Exam BoardPre-U
ModulePre-U 9794/1 (Pre-U Mathematics Paper 1)
Year2016
SessionSpecimen
Marks6
TopicFactor & Remainder Theorem
TypeFully specified polynomial: verify factor and solve
DifficultyModerate -0.8 This is a straightforward application of the factor theorem requiring substitution to verify x=2 is a root, then polynomial division to find the quadratic factor, followed by solving a simple quadratic. All steps are routine with no problem-solving insight needed, making it easier than average but not trivial since it requires multiple standard techniques.
Spec1.02f Solve quadratic equations: including in a function of unknown1.02j Manipulate polynomials: expanding, factorising, division, factor theorem

4
  1. Show that \(x = 2\) is a root of the equation \(2 x ^ { 3 } - x ^ { 2 } - 15 x + 18 = 0\).
  2. Hence solve the equation \(2 x ^ { 3 } - x ^ { 2 } - 15 x + 18 = 0\).

Question 4(i)
- \(\text{f}(-2) = 0\) clearly shown — B1
Question 4(ii)
- Method shown e.g. division — M1
- Obtain \(2x^2 + 3x - 9\) — A1
- Attempt to solve quadratic \(\big((2x-3)(x+3)\big)\) — M1
- \(x = \frac{3}{2}\) — B1ft
- \(x = 2\) and \(x = -3\) — B1ft
Total: 6 marks
**Question 4(i)**
- $\text{f}(-2) = 0$ clearly shown — B1

**Question 4(ii)**
- Method shown e.g. division — M1
- Obtain $2x^2 + 3x - 9$ — A1
- Attempt to solve quadratic $\big((2x-3)(x+3)\big)$ — M1
- $x = \frac{3}{2}$ — B1ft
- $x = 2$ and $x = -3$ — B1ft

**Total: 6 marks**
4 (i) Show that $x = 2$ is a root of the equation $2 x ^ { 3 } - x ^ { 2 } - 15 x + 18 = 0$.\\
(ii) Hence solve the equation $2 x ^ { 3 } - x ^ { 2 } - 15 x + 18 = 0$.

\hfill \mbox{\textit{Pre-U Pre-U 9794/1 2016 Q4 [6]}}