Pre-U Pre-U 9794/1 2016 June — Question 8 4 marks

Exam BoardPre-U
ModulePre-U 9794/1 (Pre-U Mathematics Paper 1)
Year2016
SessionJune
Marks4
TopicIntegration by Parts
TypeIndependent multi-part (different techniques)
DifficultyModerate -0.3 Part (a) is a standard single-application integration by parts with simple limits requiring exact evaluation. Part (b) is a routine algebraic manipulation (polynomial division or rewriting as 1 - 2/(x+1)) followed by direct integration. Both are textbook exercises requiring only technique recall with no problem-solving insight, making this slightly easier than average.
Spec1.08i Integration by parts1.08j Integration using partial fractions

8
  1. Evaluate exactly \(\int _ { 0 } ^ { 1 } x \mathrm { e } ^ { - x } \mathrm {~d} x\).
  2. Find \(\int \frac { x - 1 } { x + 1 } \mathrm {~d} x\).

(a)
Use integration by parts with \(f(x) = x\) and \(g'(x) = e^{-x}\) M1
Obtain \(-xe^{-x} - e^{-x}\) A1
Substitute limits in the correct order with subtraction. This must be seen if wrong answer obtained M1
Obtain \(1 - \frac{2}{e}\) with no sight of decimals A1
[4]
(b)
Use \(u = x+1\) and substitute into the given integral M1
Obtain \(\int\frac{u-2}{u}\mathrm{d}u\) A1
Simplify to two terms and integrate or use by parts if integrating \(u^{-1}\) and differentiating \((u-2)\) M1
AnswerMarks Guidance
Obtain \(x + 1 - 2\lnx+1 + C\) (A0 for omission of mod signs or \(+C\)) A1
[4]
*Alternative method 1:*
Obtain \(1 + \frac{k}{x+1}\) M1
Obtain \(1 - \frac{2}{x+1}\) A1
Attempt to integrate to obtain \(x + k\ln(x+1)\) M1
AnswerMarks Guidance
Obtain \(x - 2\lnx+1 + C\) (A0 for omission of mod signs or \(+C\)) A1
*Alternative method 2:*
Use parts on \((x-1)(x+1)^{-1}\) and obtain \((x-1)\ln(x+1)\) with a valid attempt at \(\int\ln(x+1)\mathrm{d}x\) M1
Find \(\int\ln(x+1)\mathrm{d}x\), dealing with \(\int\frac{x}{x+1}\mathrm{d}x\) M1
Obtain \((x-1)\ln(x+1) - (x+1)\ln(x+1) + (x+1)\) A1
AnswerMarks Guidance
Obtain \(x - 2\lnx+1 + C\) A1
**(a)**
Use integration by parts with $f(x) = x$ and $g'(x) = e^{-x}$ **M1**

Obtain $-xe^{-x} - e^{-x}$ **A1**

Substitute limits in the correct order with subtraction. This must be seen if wrong answer obtained **M1**

Obtain $1 - \frac{2}{e}$ with no sight of decimals **A1**

**[4]**

**(b)**
Use $u = x+1$ and substitute into the given integral **M1**

Obtain $\int\frac{u-2}{u}\mathrm{d}u$ **A1**

Simplify to two terms and integrate or use by parts if integrating $u^{-1}$ and differentiating $(u-2)$ **M1**

Obtain $x + 1 - 2\ln|x+1| + C$ (A0 for omission of mod signs or $+C$) **A1**

**[4]**

*Alternative method 1:*

Obtain $1 + \frac{k}{x+1}$ **M1**

Obtain $1 - \frac{2}{x+1}$ **A1**

Attempt to integrate to obtain $x + k\ln(x+1)$ **M1**

Obtain $x - 2\ln|x+1| + C$ (A0 for omission of mod signs or $+C$) **A1**

*Alternative method 2:*

Use parts on $(x-1)(x+1)^{-1}$ and obtain $(x-1)\ln(x+1)$ with a valid attempt at $\int\ln(x+1)\mathrm{d}x$ **M1**

Find $\int\ln(x+1)\mathrm{d}x$, dealing with $\int\frac{x}{x+1}\mathrm{d}x$ **M1**

Obtain $(x-1)\ln(x+1) - (x+1)\ln(x+1) + (x+1)$ **A1**

Obtain $x - 2\ln|x+1| + C$ **A1**
8
\begin{enumerate}[label=(\alph*)]
\item Evaluate exactly $\int _ { 0 } ^ { 1 } x \mathrm { e } ^ { - x } \mathrm {~d} x$.
\item Find $\int \frac { x - 1 } { x + 1 } \mathrm {~d} x$.
\end{enumerate}

\hfill \mbox{\textit{Pre-U Pre-U 9794/1 2016 Q8 [4]}}