| Exam Board | Pre-U |
|---|---|
| Module | Pre-U 9794/1 (Pre-U Mathematics Paper 1) |
| Year | 2016 |
| Session | June |
| Marks | 3 |
| Topic | Straight Lines & Coordinate Geometry |
| Type | Perpendicular line through point |
| Difficulty | Easy -1.3 This is a straightforward application of perpendicular gradients (negative reciprocal) and point-slope form. It requires only two standard steps: finding m = -1/5, then substituting the point to find c. This is simpler than typical multi-part questions and involves purely routine procedures with no problem-solving element. |
| Spec | 1.03a Straight lines: equation forms y=mx+c, ax+by+c=01.03b Straight lines: parallel and perpendicular relationships |
State $m = -\frac{1}{5}$ **B1**
Form equation $(y - 11) = (\text{their } m)(x - 1)$ or $11 = (\text{their } m)(1) + c$ **M1**
Obtain $y = -\frac{1}{5}x + \frac{56}{5}$ or equiv decimal form as final answer **A1**
**[3]**1 Find the equation of the line perpendicular to the line $y = 5 x + 6$ which passes through the point $( 1,11 )$. Give your answer in the form $y = m x + c$.
\hfill \mbox{\textit{Pre-U Pre-U 9794/1 2016 Q1 [3]}}