Pre-U Pre-U 9794/1 2016 June — Question 6 9 marks

Exam BoardPre-U
ModulePre-U 9794/1 (Pre-U Mathematics Paper 1)
Year2016
SessionJune
Marks9
TopicStationary points and optimisation
TypeFind stationary point then sketch curve
DifficultyModerate -0.3 This is a straightforward stationary points question requiring standard differentiation, solving a cubic equation that factors nicely, second derivative test, and basic curve sketching. The factorization (dy/dx = 12x²(x-3)(x-2)) is clean, and determining the range for four roots from the sketch is routine. Slightly easier than average due to the nice algebraic structure and standard techniques throughout.
Spec1.02m Graphs of functions: difference between plotting and sketching1.02n Sketch curves: simple equations including polynomials1.07n Stationary points: find maxima, minima using derivatives1.07o Increasing/decreasing: functions using sign of dy/dx

6
  1. Find the coordinates of the stationary points of the curve with equation $$y = 3 x ^ { 4 } - 20 x ^ { 3 } + 36 x ^ { 2 }$$ and determine their nature.
  2. Sketch the graph of \(y = 3 x ^ { 4 } - 20 x ^ { 3 } + 36 x ^ { 2 }\) and hence state the set of values of \(k\) for which the equation \(3 x ^ { 4 } - 20 x ^ { 3 } + 36 x ^ { 2 } = k\) has exactly four distinct real roots.

(i)
Attempt to differentiate by reducing powers by one M1
Obtain \(12x^3 - 60x^2 + 72x = 0\) A1
Factorise \(x\) and attempt to solve a 3 term quadratic (but condone cancellation of \(x\)) M1
Obtain \((0, 0)\), \((2, 32)\), \((3, 27)\) A1
Obtain the second derivative or compare gradients or \(y\) values either side of each point M1
\(36x^2 - 120x + 72\) must be used with either substitution of the relevant \(x\) values, or the final values \(72, -24\) and \(36\) must be shown and similarly for comparison of gradients.
Conclude \((0, 0)\) min, \((2, 32)\) max, \((3, 27)\) min (condone incorrect or no \(y\) values for this mark) A1
[6]
(ii)
Generally correct shape of a quartic, two min and one max M1
Stationary points marked OR correct \(y = 27\) and \(y = 32\) shown clearly A1
\(27 < k < 32\) A1
[3]
**(i)**
Attempt to differentiate by reducing powers by one **M1**

Obtain $12x^3 - 60x^2 + 72x = 0$ **A1**

Factorise $x$ and attempt to solve a 3 term quadratic (but condone cancellation of $x$) **M1**

Obtain $(0, 0)$, $(2, 32)$, $(3, 27)$ **A1**

Obtain the second derivative or compare gradients or $y$ values either side of each point **M1**

$36x^2 - 120x + 72$ must be used with either substitution of the relevant $x$ values, or the final values $72, -24$ and $36$ must be shown and similarly for comparison of gradients.

Conclude $(0, 0)$ min, $(2, 32)$ max, $(3, 27)$ min (condone incorrect or no $y$ values for this mark) **A1**

**[6]**

**(ii)**
Generally correct shape of a quartic, two min and one max **M1**

Stationary points marked OR correct $y = 27$ and $y = 32$ shown clearly **A1**

$27 < k < 32$ **A1**

**[3]**
6 (i) Find the coordinates of the stationary points of the curve with equation

$$y = 3 x ^ { 4 } - 20 x ^ { 3 } + 36 x ^ { 2 }$$

and determine their nature.\\
(ii) Sketch the graph of $y = 3 x ^ { 4 } - 20 x ^ { 3 } + 36 x ^ { 2 }$ and hence state the set of values of $k$ for which the equation $3 x ^ { 4 } - 20 x ^ { 3 } + 36 x ^ { 2 } = k$ has exactly four distinct real roots.

\hfill \mbox{\textit{Pre-U Pre-U 9794/1 2016 Q6 [9]}}