Pre-U Pre-U 9794/1 2014 June — Question 10 4 marks

Exam BoardPre-U
ModulePre-U 9794/1 (Pre-U Mathematics Paper 1)
Year2014
SessionJune
Marks4
TopicIntegration by Substitution
TypeMulti-part questions combining substitution with curve/area analysis
DifficultyModerate -0.3 Part (a) is a standard substitution (u = x² + 5) leading to a straightforward logarithm evaluation—routine for A-level. Part (b) requires substitution u = x - 2 followed by expanding and integrating term-by-term, which is slightly more involved but still a textbook exercise. Overall slightly easier than average due to the direct nature of both parts.
Spec1.08h Integration by substitution

10
  1. Show that \(\int _ { 0 } ^ { 2 } \frac { x } { x ^ { 2 } + 5 } \mathrm {~d} x = \ln \left( \frac { 3 } { \sqrt { 5 } } \right)\).
  2. Find \(\int x \sqrt { x - 2 } \mathrm {~d} x\).

(a) Attempt integration to obtain an integral in \(\ln(\mathrm{f}(x))\) — M1
Substitute limits to obtain correctly \(\frac{1}{2}(\ln 9 - \ln 5)\) — A1
Show clearly the use of at least one log law — M1
Obtain \(\ln\frac{3}{\sqrt{5}}\) www AG — A1 [4]
(b) Attempt integration by parts with \(u = x\), \(\mathrm{d}u = 1\) and \(\mathrm{d}v = (x-2)^{0.5}\) and \(v = \frac{2}{3}(x-2)^{\frac{3}{2}}\) — M1
Obtain \(kx(x-2)^{\frac{3}{2}} - m\int \mathrm{f}(x)\mathrm{d}x\) — M1
Obtain \(kg(x) - m\int(x-2)^{\frac{3}{2}}\,\mathrm{d}x\) — M1
Obtain \(\frac{2}{3}x(x-2)^{\frac{3}{2}} - \frac{4}{15}(x-2)^{\frac{5}{2}} + c\) — A1 [4]
OR
Attempt reverse substitution with \(u = x-2\), \(\mathrm{d}u = \mathrm{d}x\) and \(\sqrt{x-2} = \sqrt{u}\) — M1
Obtain \(\int(u+2)u^{0.5}\,\mathrm{d}u\) — M1
Obtain \(ku^{\frac{5}{2}} + mu^{\frac{3}{2}}\) — M1
Obtain \(\frac{2}{5}(x-2)^{\frac{5}{2}} + \frac{4}{3}(x-2)^{\frac{3}{2}} + c\) — A1
**(a)** Attempt integration to obtain an integral in $\ln(\mathrm{f}(x))$ — M1
Substitute limits to obtain correctly $\frac{1}{2}(\ln 9 - \ln 5)$ — A1
Show clearly the use of at least one log law — M1
Obtain $\ln\frac{3}{\sqrt{5}}$ www AG — A1 **[4]**

**(b)** Attempt integration by parts with $u = x$, $\mathrm{d}u = 1$ and $\mathrm{d}v = (x-2)^{0.5}$ and $v = \frac{2}{3}(x-2)^{\frac{3}{2}}$ — M1
Obtain $kx(x-2)^{\frac{3}{2}} - m\int \mathrm{f}(x)\mathrm{d}x$ — M1
Obtain $kg(x) - m\int(x-2)^{\frac{3}{2}}\,\mathrm{d}x$ — M1
Obtain $\frac{2}{3}x(x-2)^{\frac{3}{2}} - \frac{4}{15}(x-2)^{\frac{5}{2}} + c$ — A1 **[4]**

OR

Attempt reverse substitution with $u = x-2$, $\mathrm{d}u = \mathrm{d}x$ and $\sqrt{x-2} = \sqrt{u}$ — M1
Obtain $\int(u+2)u^{0.5}\,\mathrm{d}u$ — M1
Obtain $ku^{\frac{5}{2}} + mu^{\frac{3}{2}}$ — M1
Obtain $\frac{2}{5}(x-2)^{\frac{5}{2}} + \frac{4}{3}(x-2)^{\frac{3}{2}} + c$ — A1
10
\begin{enumerate}[label=(\alph*)]
\item Show that $\int _ { 0 } ^ { 2 } \frac { x } { x ^ { 2 } + 5 } \mathrm {~d} x = \ln \left( \frac { 3 } { \sqrt { 5 } } \right)$.
\item Find $\int x \sqrt { x - 2 } \mathrm {~d} x$.
\end{enumerate}

\hfill \mbox{\textit{Pre-U Pre-U 9794/1 2014 Q10 [4]}}