Pre-U Pre-U 9794/1 2014 June — Question 11 11 marks

Exam BoardPre-U
ModulePre-U 9794/1 (Pre-U Mathematics Paper 1)
Year2014
SessionJune
Marks11
TopicFirst order differential equations (integrating factor)
TypeSeparable with partial fractions
DifficultyStandard +0.3 This is a standard separable differential equation with guided steps through partial fractions. Part (i) is routine A-level algebra, part (ii) follows directly from separation and integration, and part (iii) involves straightforward substitution and rearrangement. The question structure provides significant scaffolding, making it slightly easier than average despite involving multiple techniques.
Spec1.02y Partial fractions: decompose rational functions1.08k Separable differential equations: dy/dx = f(x)g(y)

11 A differential equation is given by \(2 \frac { \mathrm {~d} y } { \mathrm {~d} x } = y ( 1 - y )\).
  1. Express \(\frac { 2 } { y ( 1 - y ) }\) in partial fractions.
  2. Hence show by integration that \(\frac { y ^ { 2 } } { ( 1 - y ) ^ { 2 } } = A \mathrm { e } ^ { x }\).
  3. Given that \(x = 0\) when \(y = 2\), find the value of \(A\) and express \(y\) in terms of \(x\).

(i) Attempt use of the form \(\frac{A}{y} + \frac{B}{1-y}\) and remove fractions — M1
Obtain \(A = 2\) — A1
Obtain \(B = 2\) — A1 [3]
(ii) Attempt to separate variables and use result from (i) — M1
Attempt integration of both sides — M1
AnswerMarks Guidance
Obtain \(2\ln y - 2\ln1-y = x + C\) aef — A1
Attempt use of at least one log law correctly — M1
State or imply \(\ln\left(\frac{y^2}{(1-y)^2}\right) = x + C\) and obtain convincingly
\(\frac{y^2}{(1-y)^2} = Ae^x\) AG — A1 [5]
(iii) Substitute \((0, 2)\) and obtain \(A = 4\) — B1
Select the correct root of \(-2\) and attempt to make \(y\) the subject — M1
i.e. \(\frac{y}{(1-y)} = -2e^{\frac{x}{2}}\)
Obtain \(y = \frac{2e^{\frac{x}{2}}}{2e^{\frac{x}{2}}-1}\) or equivalent simplified form — A1 [3]
**(i)** Attempt use of the form $\frac{A}{y} + \frac{B}{1-y}$ and remove fractions — M1
Obtain $A = 2$ — A1
Obtain $B = 2$ — A1 **[3]**

**(ii)** Attempt to separate variables and use result from (i) — M1
Attempt integration of both sides — M1
Obtain $2\ln y - 2\ln|1-y| = x + C$ aef — A1
Attempt use of at least one log law correctly — M1
State or imply $\ln\left(\frac{y^2}{(1-y)^2}\right) = x + C$ and obtain convincingly
$\frac{y^2}{(1-y)^2} = Ae^x$ AG — A1 **[5]**

**(iii)** Substitute $(0, 2)$ and obtain $A = 4$ — B1
Select the correct root of $-2$ and attempt to make $y$ the subject — M1
i.e. $\frac{y}{(1-y)} = -2e^{\frac{x}{2}}$
Obtain $y = \frac{2e^{\frac{x}{2}}}{2e^{\frac{x}{2}}-1}$ or equivalent simplified form — A1 **[3]**
11 A differential equation is given by $2 \frac { \mathrm {~d} y } { \mathrm {~d} x } = y ( 1 - y )$.\\
(i) Express $\frac { 2 } { y ( 1 - y ) }$ in partial fractions.\\
(ii) Hence show by integration that $\frac { y ^ { 2 } } { ( 1 - y ) ^ { 2 } } = A \mathrm { e } ^ { x }$.\\
(iii) Given that $x = 0$ when $y = 2$, find the value of $A$ and express $y$ in terms of $x$.

\hfill \mbox{\textit{Pre-U Pre-U 9794/1 2014 Q11 [11]}}