Pre-U Pre-U 9794/1 2014 June — Question 6 7 marks

Exam BoardPre-U
ModulePre-U 9794/1 (Pre-U Mathematics Paper 1)
Year2014
SessionJune
Marks7
TopicAreas by integration
TypeArea between curve and line
DifficultyStandard +0.3 This is a straightforward multi-part integration question requiring standard techniques: finding where a curve crosses the x-axis (solving a quadratic), differentiation to find a tangent equation, and using integration to find an area. All steps are routine A-level procedures with no novel insight required, making it slightly easier than average.
Spec1.07i Differentiate x^n: for rational n and sums1.07m Tangents and normals: gradient and equations1.08d Evaluate definite integrals: between limits1.08e Area between curve and x-axis: using definite integrals

6 The diagram shows the curve with equation \(y = 7 x - 10 - x ^ { 2 }\) and the tangent to the curve at the point where \(x = 3\). \includegraphics[max width=\textwidth, alt={}, center]{69792771-6de6-4886-9c71-e794fcb7aaba-3_648_679_342_733}
  1. Show that the curve crosses the \(x\)-axis at \(x = 2\).
  2. Find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\) and hence find the equation of the tangent to the curve at \(x = 3\). Show that the tangent crosses the \(x\)-axis at \(x = 1\).
  3. Evaluate \(\int _ { 2 } ^ { 3 } \left( 7 x - 10 - x ^ { 2 } \right) \mathrm { d } x\) and hence find the exact area of the shaded region bounded by the curve, the tangent and the \(x\)-axis.

(i) Show \(7 \times 2 - 10 - 2^2 = 0\) OR solve \(x^2 - 7x + 10 = 0\) to obtain \(x = 2\) at least — B1 [1]
(ii) Obtain \(\frac{\mathrm{d}y}{\mathrm{d}x} = 7 - 2x\) — B1
Obtain \(y = 2\) and \(\frac{\mathrm{d}y}{\mathrm{d}x} = 1\) at \(x = 3\) — B1
Attempt equation of straight line — M1
Obtain \(y = x - 1\) — A1
Substitute \(x = 1\) and obtain \(y = 0\) — A1 [5]
(iii) Obtain area of triangle \(= 2\) — B1
Attempt integration — M1
Obtain \(\left[\frac{7x^2}{2} - 10x - \frac{1}{3}x^3\right]\) — A1
Attempt to substitute limits of 2 and 3 — M1
Obtain \(\frac{7}{6}\) — A1
Attempt subtraction from area of triangle — M1
Obtain \(\frac{5}{6}\) with no decimals seen — A1 [7]
**(i)** Show $7 \times 2 - 10 - 2^2 = 0$ OR solve $x^2 - 7x + 10 = 0$ to obtain $x = 2$ at least — B1 **[1]**

**(ii)** Obtain $\frac{\mathrm{d}y}{\mathrm{d}x} = 7 - 2x$ — B1
Obtain $y = 2$ and $\frac{\mathrm{d}y}{\mathrm{d}x} = 1$ at $x = 3$ — B1
Attempt equation of straight line — M1
Obtain $y = x - 1$ — A1
Substitute $x = 1$ and obtain $y = 0$ — A1 **[5]**

**(iii)** Obtain area of triangle $= 2$ — B1
Attempt integration — M1
Obtain $\left[\frac{7x^2}{2} - 10x - \frac{1}{3}x^3\right]$ — A1
Attempt to substitute limits of 2 and 3 — M1
Obtain $\frac{7}{6}$ — A1
Attempt subtraction from area of triangle — M1
Obtain $\frac{5}{6}$ with no decimals seen — A1 **[7]**
6 The diagram shows the curve with equation $y = 7 x - 10 - x ^ { 2 }$ and the tangent to the curve at the point where $x = 3$.\\
\includegraphics[max width=\textwidth, alt={}, center]{69792771-6de6-4886-9c71-e794fcb7aaba-3_648_679_342_733}\\
(i) Show that the curve crosses the $x$-axis at $x = 2$.\\
(ii) Find $\frac { \mathrm { d } y } { \mathrm {~d} x }$ and hence find the equation of the tangent to the curve at $x = 3$.

Show that the tangent crosses the $x$-axis at $x = 1$.\\
(iii) Evaluate $\int _ { 2 } ^ { 3 } \left( 7 x - 10 - x ^ { 2 } \right) \mathrm { d } x$ and hence find the exact area of the shaded region bounded by the curve, the tangent and the $x$-axis.

\hfill \mbox{\textit{Pre-U Pre-U 9794/1 2014 Q6 [7]}}